似乎无法弄清楚如何在Flask中使用响应头

时间:2017-03-01 08:31:42

标签: python flask header response

嘿伙计们为什么我的代码无效。我忘记了大部分关于响应标题和如何使用它的东西,我很想弄清楚何时使用dict和tuple等。

from flask import Flask, jsonify, json, request, abort
from flask_sqlalchemy import SQLAlchemy

app = Flask(__name__)
app.config.from_pyfile('Config.py')
db = SQLAlchemy(app)
response = {}

class JsonModel(object): #Class for making objects JSON serializable
    def as_dict(self):
        return {c.name: getattr(self, c.name) for c in self.__table__.columns}

class User(db.Model, JsonModel): #Class which is a model for the User table in the database
    User_ID = db.Column(db.Integer, primary_key = True)
    FirstName = db.Column(db.String(20))
    LastName = db.Column(db.String(20))

def __init__(self,User_ID,FirstName, LastName):
    self.User_ID = User_ID
    self.FirstName = FirstName
    self.LastName = LastName

class Todo(db.Model, JsonModel):    #Class which is a model for the Todo table in the database
    todo_ID = db.Column(db.Integer, primary_key = True)
    UserID = db.Column(db.Integer, db.ForeignKey("user.User_ID"))
    details = db.Column(db.String(30))

def __init__(self, UserID, details):
    self.UserID = UserID
    self.details = details

@app.route('/todo', methods = ['GET'])   #Uses GET method to return all information in the database.
def index():
    return json.dumps([u.as_dict() for u in Todo.query.all()])

@app.route('/todo/<int:todo_ID>', methods = ['GET'])
def get(todo_ID):
    todo = Todo.query.get(todo_ID)
    response
    response['todo_ID']= todo.todo_ID
    response['UserID'] = todo.UserID
    response['details'] = todo.details
    response.status_code = 200
    response.headers['location'] = '/todo/{}'.format(todo.todo_ID)
    return response

运行此代码时,我收到以下错误。

File "/home/muba/PycharmProjects/Work/Flaskapp.py", line 43, in get
    response.status_code = 200
AttributeError: 'dict' object has no attribute 'status_code'
127.0.0.1 - - [01/Mar/2017 21:29:27] "GET /todo/1 HTTP/1.1" 500 -

有人可以告诉我什么是错的,并指出我的某种教程。我唯一可以理解的是,我在顶部的响应对象由于某种原因不能使用status_code。

1 个答案:

答案 0 :(得分:0)

假设您正在寻找以JSON格式返回echo $rand; 对象;下面是使用JSON对象和额外标头构建响应的简化示例。

<强> app.py

todo

卷曲响应:

from flask import Flask, make_response
import json

app = Flask(__name__)

    @app.route("/", methods=['GET'])
    def index():

    todo = {'todo_ID': 1, 'UserID': 2, 'details': 'test'}
    r = make_response((json.dumps(todo),
                       200,
                       {'Content-Type': 'application/json',
                        'location': '/todo/{}'.format(todo['todo_ID'])}))
    return r


if __name__ == "__main__":
    app.run(debug=True)