Question

你好，我有四个表，我试图从所有这些表中获取数据。表是

用户
的UserInfo
类别
UserCategory

由于用户可以选择多个类别，因此我设置了一个名为UserCategory的单独表格。此表包含user_id和cat_id作为user和Category表字段的外键

在Category表格中，字段为cat_name

我想获取与特定用户ID关联的所有四个表中的所有数据。所以目前我已经实现了这一目标。我会告诉你如何。

class UserInfo extends AppModel
{
    public $useTable = 'user_info';
    public $primaryKey = 'user_id';


    public $belongsTo = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'user_id',
            'type' => 'RIGHT',
            'fields' => array('User.user_id','User.email','User.active')
        )


    );
    public $hasMany = array(
        'UserCategory' => array(
            'className' => 'UserCategory',
            'foreignKey'    => 'user_id',
            'conditions' => array('user_id = UserCategory.user_id')
            //'order' => 'UserCategory. DESC'
        ),


    );
    public function getUserDetails($user_id){
        return $this->find('all', array(
            'conditions' => array(
                'UserInfo.user_id' => $user_id
            ),


        ));

    }

通过这样做

$userDetails = $this->UserInfo->getUserDetails($user_id);

我得到了这样的结果

Array
(
    [0] => Array
        (
            [UserInfo] => Array
                (
                    [user_id] => 9
                    [first_name] => lorem
                    [last_name] => ipsum
                    [phone_no] => 123
                    [profile_img] => app/webroot/uploads/9/589c538daa276test.png.png
                    [registration_date] => 2017-02-09 08:33:33
                    [device_token] => ddd222
                )

            [User] => Array
                (
                    [user_id] => 9
                    [email] => new email
                    [active] => 1
                )

            [UserCategory] => Array
                (
                    [0] => Array
                        (
                            [user_category_id] => 1
                            [user_id] => 9
                            [cat_id] => 1
                        )

                    [1] => Array
                        (
                            [user_category_id] => 3
                            [user_id] => 9
                            [cat_id] => 1
                        )

                    [2] => Array
                        (
                            [user_category_id] => 4
                            [user_id] => 9
                            [cat_id] => 2
                        )

                )

        )

)

我想知道如何在上面的数组中从类别表中获取类别名称。

Answer 1

在这种情况下，您可以使用containable：

public function getUserDetails($user_id) {
    $this->Behaviors->attach('Containable');
    return $this->find('all', array(
        'conditions' => array(
            'UserInfo.user_id' => $user_id
        ),
        'contain' => array(
            'User', 'UserCategory.Category'
        )
    ));
}

从多个表中获取数据Cakephp

1 个答案: