Question

我使用accessoryButtonTappedForRowWith：

呈现我的viewController

let storyboard : UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
        let popoverContent = storyboard.instantiateViewController(withIdentifier: "Test")

        popoverContent.modalPresentationStyle = .popover

        if let popover = popoverContent.popoverPresentationController {
            let viewForSource = self.createCharacterView as UIView
            popover.sourceView = viewForSource

            // the position of the popover where it's showed
            popover.sourceRect = viewForSource.bounds

            // the size you want to display
            popoverContent.preferredContentSize = CGSize(width: 200,height: 200)
            popover.delegate = self
        }

        self.present(popoverContent, animated: true, completion: nil)

弹出窗口工作正常，只是我呈现的viewController需要tableViewCell的标签。我能够获得变量，但是我不确定如何将变量传递给popover，因为没有调用segue我不认为我能够使用prepare(for segue: UIStoryboardSegue, sender: Any?)。

Answer 1

太简单了：

[Int]() is [String] // true
[1] is [String] // false

Answer 2

您可能需要将popOvercontent转换为特定的viewController

$ANDROID_HOME/tools/

Swift 3将变量传递给PopupViewController

2 个答案: