我有一堆使用redux-saga的api调用的动作观察者。问题是我想制作 ONE 动作监视器,它会激活所有这些动作观察者以获取所有api,而不必重复我已有的代码。如果其中一个观察者返回被拒绝的Promise,它应该取消所有其他观察者。这样做的最佳方式是什么?
function* watchFetchUsers() {
while(true) {
yield take([FETCH_USERS]);
try {
const users = yield call(api.fetchUserData);
yield put({ type:FETCH_USERS, payload: users });
} catch (err) {
yield put({ type:SIGNOUT, status: err });
return err;
}
}
}
function* watchFetchDepartments() {
while(true) {
yield take([FETCH_DEPARTMENTS]);
try {
const departments = yield call(api.fetchDepartmentData);
yield put({ type:FETCH_DEPARTMENTS, payload: departments });
} catch (err) {
yield put({ type:SIGNOUT, status: err });
return err;
}
}
}
function* watchFetchPositions() {
while(true) {
yield take([FETCH_POSITIONS]);
try {
const positions = yield call(api.fetchPositionData);
yield put({ type:FETCH_POSITIONS, payload: positions });
} catch (err) {
yield put({ type:SIGNOUT, status: err });
return err;
}
}
}
function* watchFetchBanks() {
while(true) {
yield take([FETCH_BANKS]);
try {
const banks = yield call(api.fetchBankData);
yield put({ type:FETCH_BANKS, payload: banks });
} catch (err) {
yield put({ type:SIGNOUT, status: err });
return err;
}
}
}
function* watchFetchAuthenticatedUser() {
while(true) {
yield take([FETCH_AUTHENTICATED_USER]);
try {
const user = yield call(api.fetchAuthenticatedUser);
yield put({ type:FETCH_AUTHENTICATED_USER, payload: user });
} catch (err) {
yield put({ type:SIGNOUT, status: err });
return err;
}
}
}
export default function* fetchData() {
yield [
fork(watchFetchUsers),
fork(watchFetchDepartments),
fork(watchFetchPositions),
fork(watchFetchBanks),
fork(watchFetchAuthenticatedUser)
];
}
答案 0 :(得分:1)
这个怎么样
export function* watchFetchAll() {
while(true) {
// const {type} = yield take(['FETCH_A', 'FETCH_B', ...]);
const {type} = yield take(action => /^FETCH_/.test(action.type));
console.log('type %s', type);
try {
const data = yield call(api.fetch, type);
console.log('data', data);
yield put({type, payload: data})
}
catch (error) {
console.log('error', error);
yield put({ type: 'SIGNOUT', status: error })
}
}
}
export default function* fetchData() {
yield *watchFetchAll();
}
简单的api实现:
const api = {
fetch(type) {
switch (type) {
case 'FETCH_A': return Promise.resolve({result: 'Fetched A type'});
case 'FETCH_B': return Promise.resolve({result: 'Fetched B type'});
// other cases
default: console.log(`Unknown type ${type}`);
}
}
};
答案 1 :(得分:0)
分叉任务的错误会传播到父任务。 我不确定下面是否是你想要的。但也许它会起作用。
function* watchFetchUsers() {
while(true) {
yield take([FETCH_USERS]);
const users = yield call(api.fetchUserData);
yield put({ type:FETCH_USERS, payload: users });
}
}
function* watchFetchDepartments() {
while(true) {
yield take([FETCH_DEPARTMENTS]);
const departments = yield call(api.fetchDepartmentData);
yield put({ type:FETCH_DEPARTMENTS, payload: departments });
}
}
function* watchFetchPositions() {
while(true) {
yield take([FETCH_POSITIONS]);
const positions = yield call(api.fetchPositionData);
yield put({ type:FETCH_POSITIONS, payload: positions });
}
}
function* watchFetchBanks() {
while(true) {
yield take([FETCH_BANKS]);
const banks = yield call(api.fetchBankData);
yield put({ type:FETCH_BANKS, payload: banks });
}
}
function* watchFetchAuthenticatedUser() {
while(true) {
yield take([FETCH_AUTHENTICATED_USER]);
const user = yield call(api.fetchAuthenticatedUser);
yield put({ type:FETCH_AUTHENTICATED_USER, payload: user });
}
}
export default function* fetchData() {
while (true) {
let tasks;
try {
tasks = yield [
fork(watchFetchUsers),
fork(watchFetchDepartments),
fork(watchFetchPositions),
fork(watchFetchBanks),
fork(watchFetchAuthenticatedUser)
];
yield join(...tasks)
} catch (e) {
yield cancel(...tasks);
yield put({ type:SIGNOUT, status: err });
}
}
}
或者,如果您不想恢复任务,
//....
export default function* fetchData() {
try {
yield [
fork(watchFetchUsers),
fork(watchFetchDepartments),
fork(watchFetchPositions),
fork(watchFetchBanks),
fork(watchFetchAuthenticatedUser)
];
} catch (e) {
yield put({ type:SIGNOUT, status: err });
}
}