Question

我在while中的while循环无法正常工作。我得到它的方式设置它并没有开始y催化后。请有人帮我这个吗

#include <stdio.h>
#pragma warning(disable:4996)
#include <stdlib.h>
#include <time.h>

void play_game();

int main()
{
 char resp;

 printf("Welcome to the game of Guess It!\n\n");
 printf("I will choose a number between 1 and 100.\n");
 printf("You will try and guess that number.If you guess wrong, I\n");
 printf("will tell you if you guessed too high or too low.\n\n");
 printf("You have six tries to guess the number.\n\n");

 play_game();

 printf("Would you like to play again? (y/n)\n");
 scanf("%c%*c",&resp);

 while((resp=='y') || (resp=='Y'))
 {
  play_game();

  printf("Would you like to play again?\n");
  scanf("%c%*c",&resp);

 }

 printf("Goodbye it was fun.\n");
 printf("Hope to play Guess It with you again soon.\n");

 return 0;
}
void play_game()
{
 int num;
 int guess = 0;
 int count = 1;
 count =1;

 srand((unsigned int)time(NULL));
 num = rand() % 100 +1;

 printf("Ok I am thinking of a number. Try to guess it.\n");
 printf("Your guess?\n");
 scanf("%d",&guess);

 while(guess != num && count != 6)
 {
  if(guess > 100 || guess < 1)
  {
   printf("Illegal guess. Your guess must be between 1 and 100.\n");
   printf("Guess again\n");
   scanf("%d", &guess);
   count ++;
  } 
  else if(guess > num)
   {
    printf("Too High! Guess again\n");
    scanf("%d", &guess);
    count ++;
   }
   else if(guess < num)
   {
    printf("Too Low! Guess again\n");
    scanf("%d", &guess);
    count ++;
   }
 }
  if (guess == num)
  {
   printf("***CORRECT***\n");
  }
  else 
   printf("Too many guesses\n");

   printf("The number is %d\n\n", num);
}

Answer 1

也许您可以在play_game函数内的scanf中添加“％* c”，以排出输入数字后可能正在输入的换行符。

Answer 2

尝试将"%c%*c"更改为"%c\n"。

scanf（）正在扫描你的键盘。我假设您想在进入印刷机后停止扫描。因此换行符“\ n”，它对应于enterpress。

您也可以使用do while而不是while。这样你只需要编写一次重复的代码。例如：

 do
 {
  play_game();

  printf("Would you like to play again?\n");
  scanf("%c%*c",&resp);

 } while((resp=='y') || (resp=='Y'))

这样，在检查条件之前执行du body内部的代码。

需要帮助调试简单的控制台游戏

2 个答案: