Rails 3.2.13,FactoryGirl,minitest-spec-rails。
我想为InvoicedItem
模型定义工厂。此InvoicedItem
属于(多态):owner
。此owner
可以是SpentItem
。为了创建SpentItem
,我需要创建其他几条记录(PricingGroup
,PriceRatio
,Supplier
等等。)这很快就会变成一场噩梦。
有没有办法在FactoryGirl中定义一个不使用现有模型的关联?
基本上,我不想实例化几个SpentItem
相关模型来测试InvoicedItem
。我只需要InvoicedItem的owner
响应以下方法:name_for_invoice
和bill_price_for_invoice
。
目前,我有这个:
要求'test_helper'
class FakeInvoicedItemOwner
attr_accessor :name_for_invoice, :bill_price_for_invoice
end
FactoryGirl.define do
factory 'FakeInvoicedItemOwner' do
name_for_invoice { 'Fake Name' }
bill_price_for_invoice { 12.0 }
end
factory 'Invoicing::InvoicedItem' do
association :invoice, factory: 'Invoicing::Invoice'
owner { FactoryGirl.build('FakeInvoicedItemOwner') }
name { 'FG name' }
billed_price { 1.0 }
end
end
我总是遇到与持久性相关的错误:undefined method 'primary_key' for FakeInvoicedItemOwner:Class
因为FactoryGirl试图保留这个FakeInvoicedItemOwner
实例,但我试图避免这种情况。有没有办法告诉FactoryGirl使用假对象而不是给真正的模型工厂?
编辑:解决方案
(命名错误,Plus::SpentItemStub
应该是Invoicing::Stubs::SpentItem
)
# class inheriting from an invoice-able item
# redefines the methods used for Invoicing
class Plus::SpentItemStub < Plus::SpentItem
def name_for_invoice
'fake name for invoicing'
end
end
FactoryGirl.define do
# factory for my fake model above
factory 'Plus::SpentItemStub' do
end
factory 'Invoicing::InvoicedItem' do
# relation owner using a stubbed instance of my fake model
owner { FactoryGirl.build_stubbed('Plus::SpentItemStub') }
# ...
end
end
答案 0 :(得分:1)
您仍然可以使用每个关系的真实模型,但使用build_stubbed
而不是build
,这应该更快更轻:
https://robots.thoughtbot.com/use-factory-girls-build-stubbed-for-a-faster-test