从cs.v

时间:2017-02-28 20:04:26

标签: java csv

我有一个.csv文件,其中包含我想要跳过的标题。当.csv文件中存在标题时出现错误但是当它被删除时程序运行完全正常。我希望我的代码跳过标题并继续进行该过程。

.csv文件是什么样的:

使模型速度燃料基础MPG ScaleFactor时间移动

Ford Mustang 0 20.2 20 0.02 2.3

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Test {

   public static void main(String[] args) throws IOException {
   List<Vehicle> cars = new ArrayList<Vehicle>();
   Scanner scanner = new Scanner(System.in);
   System.out.println("Enter the file name:");
   String filename = scanner.nextLine();
   BufferedReader reader = new BufferedReader(new FileReader(new File(
           filename.trim())));
   String line = "";


   while ((line = reader.readLine()) != null) {
       String[] words = line.split(",");


           String make = words[0];
           String model = words[1];
           int currentSpeed = Integer.parseInt(words[2]);
           double fuel = Double.parseDouble(words[3]);
           double baseMpg = Double.parseDouble(words[4]);
           double scaleFactor = Double.parseDouble(words[5]);
           double timeTravelled = Double.parseDouble(words[6]);

           Vehicle car = new Car(fuel, currentSpeed, baseMpg, scaleFactor,
                   make, model, timeTravelled);
           System.out.println(car);
           cars.add(car);


   }

   FileWriter writer=new FileWriter(new File("ProcessedCars.txt"));

   for(Vehicle car:cars)
   {
       writer.write(car.toString());
       writer.flush();
       writer.write("\r\n");

       }

   }

}

2 个答案:

答案 0 :(得分:1)

跳过while循环中的第一行:

boolean skip = true;
while ((line = reader.readLine()) != null) {
  if(skip) {
    skip = false; // Skip only the first line
    continue;
  }
  String[] words = line.split(",");
  // ...
}

答案 1 :(得分:0)

一种方法是捕获异常:

    try{
        int currentSpeed = Integer.parseInt(words[2]);
        // ...
    }catch(NumberFormatException e){
        // Failed to parse speed, input is likely a text, like header
    }

或者,如果您确定有标题,请在循环之前调用额外的readline()