Question

我创建了一个名为QMessageBox的{{1}}的子类，我希望在子类的构造函数中执行某些操作。这是我的班级：

部首：

CustomQMessageBox

.cpp的：

#ifndef CUSTOMQMESSAGEBOX_H
#define CUSTOMQMESSAGEBOX_H
#include <QMessageBox>

class CustomQMessageBox : public QMessageBox
{
public:
    CustomQMessageBox();
};

#endif // CUSTOMQMESSAGEBOX_H

当我创建#include "customqmessagebox.h" CustomQMessageBox::CustomQMessageBox() { qDebug() << "yo"; }的实例时，会调用构造函数并CustomQMessageBox说qDebug。但是，如果我调用静态API方法，则不会调用构造函数。

yo

当我使用//constructor is called CustomQMessageBox cbox; //constructor is not called CustomQMessageBox::question(this, "Title", "Question?", QMessageBox::Yes | QMessageBox::No);的静态方法时，为什么不调用构造函数？

感谢您的时间。

Answer 1

这是我经常使用的一个类，它来自QMessageBox。您可以使用构造函数来启动自定义按钮。如果你需要更具体的东西，你可以从这个课程中获得。

如果您想获得按钮角色，可以调用messageBox-＆gt; buttonRole（QAbstractButton * buttonInQuestion）;

头。

#ifndef MESSAGEBOX_H
#define MESSAGEBOX_H

#include <QMessageBox>
#include <QPushButton>

class MessageBox : public QMessageBox
{
    Q_OBJECT

public:
    MessageBox(QWidget* parent, const QString& title, const QString& text,
               QMessageBox::Icon icon = QMessageBox::NoIcon,
               const QString& btnText1 = "", QMessageBox::ButtonRole btnRole1 = QMessageBox::AcceptRole,
               const QString& btnText2 = "", QMessageBox::ButtonRole btnRole2 = QMessageBox::InvalidRole,
               const QString& btnText3 = "", QMessageBox::ButtonRole btnRole3 = QMessageBox::InvalidRole);
    virtual ~MessageBox();

    virtual QPushButton* addButton(const QString& btnText, QMessageBox::ButtonRole btnRole);
    QPushButton* button(const unsigned int& index) const;
    bool clicked_button(const unsigned int& index) const;

private:
    QPushButton *_button1;
    QPushButton *_button2;
    QPushButton *_button3;
};

#endif // MESSAGEBOX_H

类

#include "messagebox.h"

MessageBox::MessageBox(QWidget* parent, const QString& title, const QString& text,
                       QMessageBox::Icon icon,
                       const QString& btnText1, QMessageBox::ButtonRole btnRole1,
                       const QString& btnText2, QMessageBox::ButtonRole btnRole2,
                       const QString& btnText3, QMessageBox::ButtonRole btnRole3)
    : QMessageBox(icon, title, text,QMessageBox::NoButton, parent),
      _button1(0), _button2(0), _button3(0)
{
    _button1 = addButton(btnText1, btnRole1);
    _button2 = addButton(btnText2, btnRole2);
    _button3 = addButton(btnText3, btnRole3);
}

MessageBox::~MessageBox() {

}

QPushButton* MessageBox::addButton(const QString& btnText, QMessageBox::ButtonRole btnRole) {
    if (btnRole != QMessageBox::InvalidRole) {
        if (btnText.compare("") != 0) {
            return QMessageBox::addButton(btnText, btnRole);
        } else {
            QString stdText("?");
            switch (btnRole) {
            case QMessageBox::AcceptRole: stdText = tr("&OK"); break;
            case QMessageBox::RejectRole: stdText = tr("&Cancel"); break;
            case QMessageBox::YesRole: stdText = tr("&Yes"); break;
            case QMessageBox::NoRole: stdText = tr("&No"); break;
            default: break;
            }
            return QMessageBox::addButton(stdText, btnRole);
        }
    }
    return 0;
}

QPushButton* MessageBox::button(const unsigned int& index) const {
    switch(index) {
    case 0: return _button1;
    case 1: return _button2;
    case 2: return _button3;
    default: return 0;
    }
}

bool MessageBox::clicked_button(const unsigned int& index) const {
    return this->clickedButton() == button(index);
}

示例用法...

    MessageBox msg(0, tr("Add Icon"), tr("Icon list already contains this icon!"), QMessageBox::Warning);
    msg.exec()

子类化QMessageBox静态API

1 个答案: