Question

我有一个课程数据库，我可以按照我想要的方式返回课程。我无法确定如何超链接课程名称，以便我只能在新页面上显示该课程数据（full.php）。我想获取课程ID，并在full.php上使用它作为我的WHERE语句来显示其他字段。

以下是我的尝试：

echo "<table>
<tr>
<th>Course ID</th>
<th>Course Name</th>
<th>Provider Type</th>
<th>Audience</th>
<th>Provider Track</th>
<th>Course Delivery</th>

</tr>";

  while($row = mysql_fetch_array($result)) {

  echo "<tr>";
  echo "<td>" .$row['courseID'] . "</td>";
  echo "<td> <p> <strong>Course Name:</strong><a href=Full.php?name='".$courseID."'>". $row['courseName'] ."</a> </p>
             <p> <strong>Course Number:</strong>".$row['courseNumber']." </p
             <p> ".$row['courseDescription'] . " </p>
             <p> <strong>Course Length:</strong> " .$row['courseLength'] . " </p>
      </td>";
  echo "<td>" .$row['courseProviderType'] . "</td>";
  echo "<td>" .$row['courseAudience'] . "</td>";
  echo "<td>" .$row['courseTrack'] . "</td>";
  echo "<td>" .$row['courseDelivery'] . "</td>";
  echo "</tr>";
  }


echo "</table>";
mysql_close($con);
?>

Answer 1

您忘记了链接上的$ row变量。这是一个修复：

echo "<table>
<tr>
<th>Course ID</th>
<th>Course Name</th>
<th>Provider Type</th>
<th>Audience</th>
<th>Provider Track</th>
<th>Course Delivery</th>

</tr>";

  while($row = mysql_fetch_array($result)) {

  echo "<tr>";
  echo "<td>" .$row['courseID'] . "</td>";
  echo "<td> <p> <strong>Course Name:</strong><a href=Full.php?name='".$row['courseID']."'>". $row['courseName'] ."</a> </p>
             <p> <strong>Course Number:</strong>".$row['courseNumber']." </p
             <p> ".$row['courseDescription'] . " </p>
             <p> <strong>Course Length:</strong> " .$row['courseLength'] . " </p>
      </td>";
  echo "<td>" .$row['courseProviderType'] . "</td>";
  echo "<td>" .$row['courseAudience'] . "</td>";
  echo "<td>" .$row['courseTrack'] . "</td>";
  echo "<td>" .$row['courseDelivery'] . "</td>";
  echo "</tr>";
  }


echo "</table>";
mysql_close($con);
?>

在第二页上，您可以使用全局$ _GET变量$_GET['name']获取此值。

Answer 2

我建议直接从数据库行传递课程ID：

<a href=Full.php?name='".$row['courseID']."'>". $row['courseName'] ."</a>

并且可能为了清晰起见而更改属性名称：

<a href=Full.php?courseID='".$row['courseID']."'>". $row['courseName'] ."</a>

Answer 3

替换此代码

 <a href=Full.php?name='".$row['courseID']."'>". $row['courseName'] ."</a>

并缺少标签

<p> <strong>Course Number:</strong>".$row['courseNumber']." </p>

echo中的超链接将数据传递给新的PHP页面

3 个答案: