Question

作为qdap的新手，我不确定这个功能是否存在，但如果有下面提到的内容会很棒。

我的初始数据集。

ID         Keywords
1          112 mills, open heart surgery, great, great job
2          Ausie, open, heart out
3          opened, heartily, 56mg)_job, orders12
4          order, macD

在使用all_words()时，我最终得到以下数据。

   WORD     FREQ
1  great       2
2  heart       2
3  open        2
4  ausie       1
5  heartily    1
6  job         1
7  macd        1
8  mgjob       1
9  mills       1
10 opened       1
11 order        1
12 orders       1
13 out          1
14 surgery      1

是否有一种方法可以将主要数据集替换为通过all_words()出现的确切字词？

EDIT1：因此，使用all_words（）的列表应该替换数据框中的原始单词，即112 mills应该成为mills，56mg）_job应该变成mgjob。

Answer 1

它有点手动，我不知道你的数据是如何格式化的，但是做一些修补工作应该做的工作：

编辑：它没有使用qdap，但我认为这不是问题的关键部分。

第2次修改：我忘记了替换，更正了以下代码。

library(data.table)
library(tm)  # Functions with tm:: below
library(magrittr)

dt <- data.table(
  ID = 1L:4L,
  Keywords = c(
    paste('112 mills', 'open heart', 'surgery', 'great', 'great job', sep = ' '),
    paste('Ausie', 'open', 'heart out', sep = ' '),
    paste('opened', 'heartily', '56mg)_job', 'orders12', sep = ' '),
    paste('order', 'macD', sep = ' ')))

# dt_2 <- data.table(Tokens = tm::scan_tokenizer(dt[, Keywords]))
dt_2 <- dt[, .(Tokens = unlist(strsplit(Keywords, split = ' '))), by = ID]

dt_2[, Words := tm::scan_tokenizer(Tokens) %>%
       tm::removePunctuation() %>%
       tm::removeNumbers()
     ]
dt_2[, Stems := tm::stemDocument(Words)]

dt_2
#     ID    Tokens    Words    Stems
#  1:  1       112                  
#  2:  1     mills    mills     mill
#  3:  1      open     open     open
#  4:  1     heart    heart    heart
#  5:  1   surgery  surgery  surgeri
#  6:  1     great    great    great
#  7:  1     great    great    great
#  8:  1       job      job      job
#  9:  2     Ausie    Ausie     Ausi
# 10:  2      open     open     open
# 11:  2     heart    heart    heart
# 12:  2       out      out      out
# 13:  3    opened   opened     open
# 14:  3  heartily heartily heartili
# 15:  3 56mg)_job    mgjob    mgjob
# 16:  3  orders12   orders    order
# 17:  4     order    order    order
# 18:  4      macD     macD     macD

# Frequencies
dt_2[, .N, by = Words]
#        Words N
#  1:          1
#  2:    mills 1
#  3:     open 2
#  4:    heart 2
#  5:  surgery 1
#  6:    great 2
#  7:      job 1
#  8:    Ausie 1
#  9:      out 1
# 10:   opened 1
# 11: heartily 1
# 12:    mgjob 1
# 13:   orders 1
# 14:    order 1
# 15:     macD 1

第二次编辑：

res <- dt_2[, .(Keywords = paste(Words, collapse = ' ')), by = ID]
res
#    ID                                  Keywords
# 1:  1  mills open heart surgery great great job
# 2:  2                      Ausie open heart out
# 3:  3              opened heartily mgjob orders
# 4:  4                                order macD

第3次修改，以防您的关键字作为列表出现，并且您希望保持这种方式。

library(data.table)
library(tm)  # Functions with tm:: below
library(magrittr)

dt <- data.table(
  ID = 1L:4L,
  Keywords = list(
    c('112 mills', 'open heart', 'surgery', 'great', 'great job'),
    c('Ausie', 'open', 'heart out'),
    c('opened', 'heartily', '56mg)_job', 'orders12'),
    c('order', 'macD')))

dt_2 <- dt[, .(Keywords = unlist(Keywords)), by = ID]
dt_2[, ID_temp := .I]

dt_3 <- dt_2[, .(ID, Tokens = unlist(strsplit(unlist(Keywords), split = ' '))), by = ID_temp]

dt_3[, Words := tm::scan_tokenizer(Tokens) %>%
       tm::removePunctuation() %>%
       tm::removeNumbers() %>%
       stringr::str_to_lower()
     ]
dt_3[, Stems := tm::stemDocument(Words)]
dt_3

res <- dt_3[, .(
  ID = first(ID),
  Keywords = paste(Words, collapse = ' ') %>% stringr::str_trim()),
  by = ID_temp]
res <- res[, .(Keywords = list(Keywords)), by = ID]

# Confirm format (a list of keywords in every element)
dt[1, Keywords] %T>% {print(class(.))} %T>% {print(length(.[[1]]))}
res[1, Keywords] %T>% {print(class(.))} %T>% {print(length(.[[1]]))}

使用all_words

1 个答案: