为什么这个字段分隔符正则表达式不允许我提取所需的值？

Question

我的输入文件sumacomando如下所示：

"firstName": "gdrgo",   "xxxxx": "John", "xxxxx": "John", "xxxxx": "John", "xxxxx": "John", "xxxxx": "John",   "lastName": "222",dfg
"xxxxx": "John",    "firstName": "beto",   "xxxxx": "John", "xxxxx": "John", "xxxxx": "John",   "lastName": "111","xxxxx": "John",
"xxxxx": "John",    "firstName": "beto",   "xxxxx": "John", "xxxxx": "John", "xxxxx": "John",   "lastName": "111","xxxxx": "John",
"xxxxx": "John",   "xxxxx": "John",    "firstName": "beto2", "xxxxx": "John","lastName": "555", "xxxxx": "John","xxxxx": "John",
"xxxxx": "John",   "xxxxx": "John",    "firstName": "beto2", "xxxxx": "John","lastName": "444", "xxxxx": "John","xxxxx": "John",
"firstName": "gdrgo",   "xxxxx": "John", "xxxxx": "John", "xxxxx": "John", "xxxxx": "John", "xxxxx": "John",   "lastName": "222",dfg
"xxxxx": "John",   "xxxxx": "John",    "firstName": "beto2", "xxxxx": "John","lastName": "444", "xxxxx": "John","xxxxx": "John",

我使用这个命令：

awk -v RS="\n" \
    -v FS='firstName": "|",[^+]*lastName": "|",' \
    '{sum[$1]=$2;} {print sum[$1]}' sumacomando

输出：

gdrgo
111
111
555
444
gdrgo
444

但我期待这个：

222
111
111
555
444
222
444

我做错了什么？

Answer 1

输入有点不规则，并不清楚数组sum的用途是什么，但要准确地告诉你你要求的是什么：

awk -F'^.*"lastName": "|",' '{ print $2 }' sumacomando

字段分隔符正则表达式'^.*"lastName": "|",'匹配从行的开头到"lastName": "的所有内容，然后匹配",，以便第二个字段 - $2 - 有效地成为lastName字段的相关值的内容。