我正在参加摄影比赛并且有这样的关系
以下是项目中的实体：
图像
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Image {
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @ORM\Column(type="string", length=255, name="file_name")
* @var string $fileName
*/
protected $fileName;
/**
* @ORM\Column(type="string", length=255, name="title", nullable=true)
* @var string $title
*/
protected $title = null;
/**
* @ORM\Column(type="string", length=255, name="author", nullable=true)
* @var string $author
*/
protected $author = null;
/**
* @ORM\Column(type="datetime", name="upload_at")
*/
protected $uploadDate;
/**
* @ORM\Column(type="boolean", name="in_pool")
*/
protected $inPool;
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set fileName
*
* @param string $fileName
*
* @return Image
*/
public function setFileName($fileName)
{
$this->fileName = $fileName;
return $this;
}
/**
* Get fileName
*
* @return string
*/
public function getFileName()
{
return $this->fileName;
}
/**
* Set title
*
* @param string $title
*
* @return Image
*/
public function setTitle($title)
{
$this->title = $title;
return $this;
}
/**
* Get title
*
* @return string
*/
public function getTitle()
{
return $this->title;
}
/**
* Set author
*
* @param string $author
*
* @return Image
*/
public function setAuthor($author)
{
$this->author = $author;
return $this;
}
/**
* Get author
*
* @return string
*/
public function getAuthor()
{
return $this->author;
}
/**
* Set uploadDate
*
* @param \DateTime $uploadDate
*
* @return Image
*/
public function setUploadDate($uploadDate)
{
$this->uploadDate = $uploadDate;
return $this;
}
/**
* Get uploadDate
*
* @return \DateTime
*/
public function getUploadDate()
{
return $this->uploadDate;
}
/**
* Set inPool
*
* @param boolean $inPool
*
* @return Image
*/
public function setInPool($inPool)
{
$this->inPool = $inPool;
return $this;
}
/**
* Get inPool
*
* @return boolean
*/
public function getInPool()
{
return $this->inPool;
}
public function __construct()
{
$this->uploadDate = new \DateTime('now');
$this->inPool = false;
}
}
投票
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use AppBundle\Entity\Image;
/**
* @ORM\Entity
*/
class Vote
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @ORM\ManyToOne(targetEntity="AppBundle\Entity\Image")
* @ORM\JoinColumn(onDelete="CASCADE")
*/
protected $image;
/**
* @ORM\Column(type="datetime", name="date")
*/
protected $date;
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set date
*
* @param \DateTime $date
*
* @return Vote
*/
public function setDate($date)
{
$this->date = $date;
return $this;
}
/**
* Get date
*
* @return \DateTime
*/
public function getDate()
{
return $this->date;
}
public function __construct()
{
$this->date = new \DateTime('now');
}
/**
* Set image
*
* @param \AppBundle\Entity\Image $image
*
* @return Vote
*/
public function setImage(Image $image = null)
{
$this->image = $image;
return $this;
}
/**
* Get image
*
* @return \AppBundle\Entity\Image
*/
public function getImage()
{
return $this->image;
}
}
现在在我的主页面上，我有一个简单的查询构建器，在表格中显示所有具有属性的图像。
现在我想在表格的每一行添加一个字段，显示每张图片的投票数。
这意味着我需要获取每行的count，其id为当前图像的id。
使用QueryBuilder实现此目的的最佳方法是什么？
请注意，我想获取所有图片的值
答案 0 :(得分：0)
在投票中添加inversedBy
/**
* @ORM\ManyToOne(targetEntity="Image", inversedBy="votes")
* @ORM\JoinColumn(onDelete="CASCADE")
*/
private $image;
添加属性$ votes
/**
* One image has many votes
* @ORM\OneToMany(targetEntity="Vote", mappedBy="image")
*/
private $votes;
function __construct() {
$this-> votes = new ArrayCollection()
}
然后使用getter你可以获得选票：
function getVotes()
{
return $this->votes;
}
和ArrayCollection具有count（）方法，因此您可以使用它来获得投票数
答案 1 :(得分：0)
在Vote实体的存储库类中（它应该是VoteRepository，如果它已经存在，则创建此类）添加方法countVotesForImage：
/**
* Method returns count of votes assigned to an Image entity
*
* @param Image $image Instance of Image entity
*
* @return int Result of count query
*/
public function countVotesForImage(Image $image)
{
$imageID = $image->getId();
if (!is_numeric($imageID)) {
// for new images which are not stored in DB
// we dont have to query database
return 0;
}
return (int) $this->createQueryBuilder('v')
->select('COUNT(v.id)')
->where('v.image = :id')
->setParameter('id', $image->getId())
->getQuery()
->getSingleScalarResult();
}
在任何控制器中，您都可以使用它：
$image; // this variable should contain valid class of Image entity
$counter = $this->getDoctrine()->getRepository('AppBundle:Vote')
->countVotesForImage($image);
最后一步是将其传递给视图：
return $this->render(
'your/template.html.twig',
array('counter' => $counter)
);
如果您想对所有图片进行所有投票，请将此方法添加到ImageRepository：
/**
* Method returns count of votes assigned to an Image entity
*
* @return ArrayCollection
*/
public function countVotesForAllImages()
{
return $this->createQueryBuilder('i')
->select(array(
'i',
'COUNT(i.id) as counter'
))
->join('i.votes', 'v')
->groupBy('i.id')
->getQuery()
->getResult();
}
如果添加此方法，您还需要添加投票实体：
/**
* This is internal variable, it does not have to be mapped into database field
* @var int Counter of votes for an Image
*/
private $counter;
/**
* Method sets internal counter of votes for an Image
*
* @param int $counter
*/
public function setCounter($counter)
{
$this->counter = $counter;
}
/**
* Method gets internal counter of votes for an Image
*
* @return int
*/
public function getCounter()
{
return $this->counter;
}
@Markownikow提出的方法也可以使用，但它将所有投票从DB存入内存，水合它们，并在计数后作为内存中的数组项。由于这可能是一种矫枉过正，我建议选择我的方法。