从字符串中删除特殊字符

时间:2017-02-27 20:36:40

标签: ios swift

我正在尝试使用iOS应用拨打号码。问题是该号码采用以下格式:

  

po placeAnnotation.mapItem.phoneNumber!
  “+1(832)831-6486”

我想摆脱一些特殊字符,我想要以下内容:

  

832-831-6486

我使用了以下代码,但它没有删除任何内容:

let charactersToRemove = CharacterSet(charactersIn: "()+-")
var telephone = placeAnnotation.mapItem.phoneNumber?.trimmingCharacters(in: charactersToRemove)

有什么想法吗?

6 个答案:

答案 0 :(得分:19)

placeAnnotation.mapItem.phoneNumber!.components(separatedBy: CharacterSet.decimalDigits.inverted)
    .joined()

你走了!

我测试并运作良好。enter image description here

答案 1 :(得分:3)

如果你想要一些类似于CharacterSet的东西具有一定的灵活性,这应该有效:

let phoneNumber = "1 (832) 831-6486"

let charsToRemove: Set<Character> = Set("()+-".characters)
let newNumberCharacters = String(phoneNumber.characters.filter { !charsToRemove.contains($0) })
print(newNumberCharacters) //prints 1 832 8316486

答案 2 :(得分:0)

我知道这个问题已经回答了,但是要以任何方式格式化电话号码,可以使用下面的自定义格式化程序

class PhoneNumberFormatter:Formatter
{
  var numberFormat:String = "(###) ### ####"

  override func string(for obj: Any?) -> String? {

    if let number = obj as? NSNumber
    {
      var input = number as Int64
      var output = numberFormat
      while output.characters.contains("#")
      {
        if let range = output.range(of: "#", options: .backwards)
        {
           output = output.replacingCharacters(in: range, with: "\(input % 10)")
           input /= 10
        }
        else
        {
          output.replacingOccurrences(of: "#", with: "")
        }
      }
      return output
    }
    return nil
  }

  func string(from number:NSNumber) -> String?
  {
    return string(for: number)
  }

}


let phoneNumberFormatter = PhoneNumberFormatter()
//Digits will be filled backwards in place of hashes. It is easy change the custom formatter in anyway 
phoneNumberFormatter.numberFormat = "###-##-##-##-##"
phoneNumberFormatter.string(from: 18063783889)

答案 3 :(得分:0)

Swift 3

func removeSpecialCharsFromString(_ str: String) -> String {
        struct Constants {
            static let validChars = Set("1234567890-".characters)
        }
        return String(str.characters.filter { Constants.validChars.contains($0) })
    }

使用

let str : String = "+1 (832) 831-6486"
let newStr : String = self.removeSpecialCharsFromString(str)
print(newStr)

注意:您可以在执行操作后在字符串中添加所需的validChars。

答案 4 :(得分:0)

如果您使用字符串格式的数字和特殊字符,请使用以下代码删除特殊字符

let numberWithSpecialChar = "1800-180-0000" 

let actulNumber = numberWithSpecialChar.components(separatedBy: CharcterSet.decimalDigit.inverted).joined()

否则,如果您具有String格式的字符和特殊字符,请使用以下代码删除特殊字符

let charactersWithSpecialChar = "A man, a plan, a cat, a ham, a yak, a yam, a hat, a canal-Panama!" 

let actulString = charactersWithSpecialChar.components(separatedBy: CharacterSet.letters.inverted).joined(separator: " ")

答案 5 :(得分:-2)

NSString *str = @"(123)-456-7890";
NSLog(@"String: %@", str);

// Create character set with specified characters
NSMutableCharacterSet *characterSet = 
  [NSMutableCharacterSet characterSetWithCharactersInString:@"()-"];

// Build array of components using specified characters as separtors
NSArray *arrayOfComponents = [str componentsSeparatedByCharactersInSet:characterSet];

// Create string from the array components
NSString *strOutput = [arrayOfComponents componentsJoinedByString:@""];

NSLog(@"New string: %@", strOutput);