Question

我需要为xcode启动一个终端命令。这是命令：

sudo xattr -d -r com.test.exemple /Desktop/file.extension

我试过了

   let task = Process()
        task.launchPath = "/usr/sbin/xattr"
        task.arguments = ["-d","-r", "com.test.exemple"," /Desktop/file.extension"]
        let pipe = Pipe()
        task.standardOutput = pipe
        task.standardError = pipe
        task.launch()
        task.waitUntilExit()
        let data = pipe.fileHandleForReading.readDataToEndOfFile()
        let output : String = NSString(data: data, encoding: String.Encoding.utf8.rawValue) as! String
        print(output)

Answer 1

这是使用命令之间的管道来实现它的一种方法。我验证了当我在注释掉的行中使用参数时，文件由超级用户创建。

它正在做的是：

echo'password'| sudo -S / usr / bin / xattr -d -r com.test.exemple /Desktop/file.extension

{{1}}

Answer 2

我在阅读这篇较新的 question 后遇到了这个问题。以防万一有人通过搜索到达这里，这里是我的 answer 到该问题的代码。

实际上没有必要通过 echo 进行管道传输；以下工作正常：以下更直接的方法经过测试并有效：

import Foundation

let password = "äëïöü"
let passwordWithNewline = password + "\n"
let sudo = Process()
sudo.launchPath = "/usr/bin/sudo"
sudo.arguments = ["-S", "/bin/ls"]
let sudoIn = Pipe()
let sudoOut = Pipe()
sudo.standardOutput = sudoOut
sudo.standardError = sudoOut
sudo.standardInput = sudoIn
sudo.launch()

// Show the output as it is produced
sudoOut.fileHandleForReading.readabilityHandler = { fileHandle in
    let data = fileHandle.availableData
    if (data.count == 0) { return }
    print("read \(data.count)")
    print("\(String(bytes: data, encoding: .utf8) ?? "<UTF8 conversion failed>")")

}
// Write the password
sudoIn.fileHandleForWriting.write(passwordWithNewline.data(using: .utf8)!)

// Close the file handle after writing the password; avoids a
// hang for incorrect password.
try? sudoIn.fileHandleForWriting.close()

// Make sure we don't disappear while output is still being produced.
sudo.waitUntilExit()
print("Process did exit")

关键是你必须在密码后添加一个换行符。

从MacOS App Swift启动sudo命令

2 个答案: