使用表单操作从html页面运行时,登录验证的PHP代码正常工作,但是当使用ajax脚本运行时,它无法加载。
不涉及数据库的PHP代码似乎运行正常。
的JavaScript
< script src = "https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js" > < /script> <
script >
$(document).ready(function() {
$("#login").submit(function(event) { //Trigger on form submit
$('#name + .throw_error').empty(); //Clear the messages first
$('#success').empty();
var postForm = { //Fetch form data
'name': $('input[name=name]').val(),
'password': $('input[name=password]').val() //Store name fields value
};
$.ajax({ //Process the form using $.ajax()
type: 'POST', //Method type
url: '.php', //Your form processing file url
data: postForm, //Forms name
dataType: 'json',
success: function(data) {
if (!data.success) { //If fails
if (data.errors.name) { //Returned if any error from process.php
$('.throw_error').fadeIn(1000).html(data.errors.name).append('<p>' + data.error + '</p>'); //Throw relevant error
alert("Nope");
}
} else {
$('#success').fadeIn(1000).append('<p>' + data.name + '</p>'); //If successful, than throw a success message
alert("yes");
}
}
});
event.preventDefault(); //Prevent the default submit
});
}); < /script>
PHP代码
<?php
$errors = array();
$form_data = array();
include("config.php");
if (session_status() == PHP_SESSION_NONE) {
session_start();}
else{
$_SESSION['ses']="Already in session":
/* Write already in session code */
}
if($_SERVER["REQUEST_METHOD"] == "POST") {
// username and password sent from form
$myusername = mysqli_real_escape_string($db,$_POST['username']);
$mypassword = mysqli_real_escape_string($db,$_POST['password']);
$sql = "SELECT * FROM users WHERE user_name = '$myusername' and password = '$mypassword'";
$result = mysqli_query($db,$sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$count = mysqli_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row
if (empty($_POST['name'])) { //Name cannot be empty
$errors['name'] = 'Name cannot be blank';
}
if (!empty($errors)) { //If errors in validation
$form_data['success'] = false;
$form_data['errors'] = $errors;
}
else{
if($count == 1) {
$_SESSION['login_user'] = $myusername;
}else {
$error = "Your Login Name or Password is invalid";
$_SESSION["error"] = $error;
}
}
}
echo json_encode($form_data);
?>