Question

我正在尝试将json数组打印到其值中我在json解码后有以下数组，我需要在循环中打印它，因为它有很多项。例如，我必须打印值 firstName，lastName ，我将如何打印它。

stdClass Object ( [content] => Array ( [0] => stdClass Object ( [id] => 5 [firstName] => Ali [lastName] => S [profilePhotoUrl] => https://prn-spe-images.s3-ap-southeast-1.amazonaws.com/user-profiles/5.jpg [handle] => aliya ) [1] => stdClass Object ( [id] => 69 [handle] => hhtc ) ) [last] => 1 [totalPages] => 1 [totalElements] => 2 [numberOfElements] => 2 [first] => 1 [sort] => [size] => 10 [number] => 0 )

我做过的示例代码：

$arrayl = gettviewers($post->id,10);
foreach($arrayl as $valuel) {
  print $value1->content->firstName;
}

但它没有印刷任何价值。

###以下答案中的完整工作代码：###

帮助文件：

 ####### --- Get live viwers list for each broadcast --- ########
if ( ! function_exists('gettviewers'))
{ 
      function gettviewers($broId,$size){
      $CI =& get_instance();
      $url = API_SERVER.'broadcasts/public/'.$broId.'/top-viewers?size='.$size; 
      $json = json_decode(file_get_contents($url), true);
      return $json;
      }   
}

在视图中：

$arrayl = gettviewers($post->id, WI_LIVEUSERSIZE);
              foreach($arrayl as $value1) 
                { 
                 print $value1[0][firstName];
                 }

Answer 1

试试这个

$arrayl = gettviewers($post->id,10);


    if (is_object($arrayl)) {
        // Gets the properties of the given object
        // with get_object_vars function
        $arrayl = get_object_vars($arrayl);
    }

    if (is_array($arrayl)) {
        /*
        * Return array converted to object
        * Using __FUNCTION__ (Magic constant)
        * for recursive call
        */
        $arrayl = array_map(__FUNCTION__, $arrayl);
    }
    else {
        // Return array
        return $arrayl;
    }

var_dump($arrayl) or print_r($arrayl);

或

 foreach($arrayl as $key=>$val){
     echo $val->content[$key]
    }

Answer 2

您可以使用json_decode

实现此目的

json_decode将有效的JSON转换为stdClass-Object。

试试这个：

$arrayl = json_decode(gettviewers($post->id, 10));

foreach($arrayl as $value1) 
{
  print $value1->content->firstName;
}

Answer 3

Foreach＆＃39;采取＆＃39;对象或数组的每个元素。所以当你预先做好$value1 isn＆t;

时

stdClass Object ( [content] => Array ( [0] => stdClass Object ( [id] => 5 [firstName] => Ali [lastName] => S [profilePhotoUrl] => https://prn-spe-images.s3-ap-southeast-1.amazonaws.com/user-profiles/5.jpg [handle] => aliya ) [1] => stdClass Object ( [id] => 69 [handle] => hhtc ) ) [last] => 1 [totalPages] => 1 [totalElements] => 2 [numberOfElements] => 2 [first] => 1 [sort] => [size] => 10 [number] => 0 )

但是

[content] => Array ( [0] => stdClass Object ( [id] => 5 [firstName] => Ali [lastName] => S [profilePhotoUrl] => https://prn-spe-images.s3-ap-southeast-1.amazonaws.com/user-profiles/5.jpg [handle] => aliya ) [1] => stdClass Object ( [id] => 69 [handle] => hhtc ) ) [last] => 1 [totalPages] => 1 [totalElements] => 2 [numberOfElements] => 2 [first] => 1 [sort] => [size] => 10 [number] => 0

所以$value1已经[content]了。另外你应该注意[content]是一个数组，所以你必须这样做

$arrayl = gettviewers($post->id,10);
foreach($arrayl as $valuel) {
  print $value1[0]->firstName;
}

或在第一个内部使用第二个foreach循环。

Answer 4

要打印json_encoded数组，请执行此操作

print_r($array);

或只是做

declare @tt TABLE ( 
     logId INT, iId INT, 
     dt DATETIME, atId  INT  

INSERT @tt (logId, iId, 
    dt, atId) values 
(1, 1, '2017-01-01 09:00', 1),
(2, 1, '2017-01-01 11:00', 1),
(3, 1, '2017-01-01 14:00', 4),
(4, 1, '2017-01-01 16:00', 4),
(5, 1, '2017-01-01 20:00', 1),
(6, 1, '2017-01-01 21:00', 4),
(7, 1, '2017-01-02 09:00', 4),
(8, 2, '2017-01-02 10:00', 1),
(9, 1, '2017-01-02 11:00', 1),
(10, 1, '2017-01-02 14:00', 1),
(11, 2, '2017-01-02 15:00', 4),
(12, 1, '2017-01-02 16:00', 1),
(13, 1, '2017-01-02 17:00', 1),
(14, 1, '2017-01-02 18:00', 1),
(15, 2, '2017-01-02 15:00', 1)

Select s.logId startLogid, e.logId endLogId, 
       s.iID, s.dt startTime, e.dt endTime 
from @tt s join @tt e
    on e.logId = 
       (Select min(logId) from @tt
        where iId = s.iID
            and atId = 1
            and logId > s.logId)                
where s.aTid = 4 
      and ((Select atId from @tt
            Where logId = 
               (Select Max(logId) from @tt
                where logId < s.LogId 
                 and iId = s.iId)) = 1
        or Not Exists 
           (Select * from @tt
            Where logId < s.LogId 
              and iId = s.iID))

解码后

。

如何通过json响应打印数组返回的值？

4 个答案: