Question

我有运动队积分榜，有一个专栏“积分”（每场比赛* 3 +每场并列比赛）。

------------------------------------------
Name | Played | Won | Lost | Tied | Points
------------------------------------------
  A  |   3    |  2  |  1   |   0  |   6
  B  |   3    |  2  |  1   |   0  |   6
... (other rows not listed)

我按点分，然后直接匹配。 现在让我们说“B”赢了“A”，所以A应该先列出来。我该怎么做？

这是我的表格

CREATE TABLE IF NOT EXISTS `games` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `hometeam` int(11) NOT NULL,
  `awayteam` int(11) NOT NULL,
  `won` enum('home','away','tie') DEFAULT NULL,
  `home_score` tinyint(3) unsigned DEFAULT NULL,
  `away_score` tinyint(3) unsigned DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8;


CREATE TABLE IF NOT EXISTS `teams` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(32) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8;

我以这种方式得到我的排名表：

SELECT 
    tt.name
    ,(SELECT COUNT(*) FROM games tg WHERE (tt.id = tg.hometeam OR tt.id = tg.awayteam) AND tg.won IS NOT NULL) as `games_played`
    ,(SELECT COUNT(*) FROM games tg WHERE (tt.id = tg.hometeam AND tg.won = "home") OR (tt.id = tg.awayteam AND tg.won = "away")) as `games_won`
    ,(SELECT COUNT(*) FROM games tg WHERE (tt.id = tg.hometeam AND tg.won = "away") OR (tt.id = tg.awayteam AND tg.won = "home")) as `games_lost`
    ,(SELECT COUNT(*) FROM games tg WHERE (tt.id = tg.hometeam OR tt.id = tg.awayteam) AND tg.won = "tied") as `games_tied`
    ,(SELECT `games_won`*3 + `games_tied`) AS `points`
FROM
    teams tt
ORDER BY `points` DESC

Mysql通过比较排序行

0 个答案: