Question

      Date             Time        Mode ID
    2017-01-01  13:00:00.0000000    3   10
    2017-01-01  14:00:00.0000000    1   10
    2017-01-01  15:00:00.0000000    3   10
    2017-01-01  15:30:00.0000000    1   10

这是一个临时表。我只想将时间列显示为2列，1列显示模式= 3，其他模式= 1。

这是临时表。我只想要以下输出：

          Date         InTime(Mode-3)    OutTime(Mode-1)     ID

         2017-01-01   13:00:00.0000000  14:00:00.0000000    10

         2017-01-01   15:00:00.0000000  15:30:00.0000000    10

Answer 1

猜测您想要一种方法来创建具有固定值（1和3）的交替行。你可以用

ROW_NUMBER（）结束时的情况（按[日期]排序）％2 = 0然后1其他3

作为模式列的逻辑

Answer 2

试试这个，

DECLARE @TB TABLE (DATETIME VARCHAR(30),ID INT)
INSERT INTO @TB VALUES
('2017-01-01 13:00:00.0000000',10),
('2017-01-01 14:00:00.0000000',10),
('2017-01-01 15:00:00.0000000',10),
('2017-01-01 15:30:00.0000000',10 )

SELECT  SUBSTRING(DATETIME,0,11) DATE
        ,SUBSTRING(DATETIME,12,LEN(DATETIME)) TIME
        ,CASE WHEN ROW_NUMBER() OVER (ORDER BY DATETIME)%2 = 0 THEN 1 ELSE 3 END MODE
        ,ID
FROM    @TB

Answer 3

这有效，具体取决于数据和数据类型/架构（如果表的名称是 timeTable ）：

    SELECT DATE, time AS 'InTime(Mode-3)',
      (SELECT TOP 1 time FROM timeTable
          WHERE mode = 1 
            AND id = outerTable.id 
            AND date = outerTable.date 
            AND time > outerTable.time 
          ORDER BY date, time) AS 'OutTime(Mode-1)',
      ID
    FROM timeTable AS outerTable 
    WHERE mode = 3

outerQuery仅选择in-times mode = 3
  innerQuery中的
选择与所选时间相对应的下一个输出时间，并且仅返回第一个输出时间。按日期和时间排序，应该是下一个。 仅使用您的给定数据进行测试

输出

    Date       |  InTime(Mode-3)     |   OutTime(Mode-1)   |  ID
---------------|---------------------|---------------------|------
   2017-01-01  |  13:00:00.0000000   |  14:00:00.0000000   |  10
   2017-01-01  |  15:00:00.0000000   |  15:30:00.0000000   |  10

仅供参考：
我使用了这个表模式

 CREATE TABLE timeTable(
     date DATE,
     time TIME,
     mode INTEGER,
     id INTEGER
 );

<强>更新
时差：

SELECT *, DATEDIFF(MINUTE,INTIME,OUTTIME) AS [DIFFERENCE] FROM (
    SELECT [DATE], [time] AS INTIME,
      (SELECT TOP 1 [time] FROM timeTable
          WHERE [mode] = 1 
            AND [id] = outerTable.id 
            AND [date] = outerTable.date 
            AND [time] > outerTable.time 
          ORDER BY [date], [time]) AS OUTTIME,
      [ID]
    FROM [timeTable] AS outerTable 
    WHERE [mode] = 3
) WholeData

如何在sql中透视临时表

3 个答案: