如何在加入列表时避免换行上的空格

Question

newContents = ['The', 'crazy', 'panda', 'walked', 'to', 'the', 'Maulik', 'and', 'then', 'picked.', 'A', 'nearby', 'Ankur', 'was\n', 'unaffected', 'by', 'these', 'events.\n']
print(' '.join(newContents))

输出：

The crazy panda walked to the Maulik and then picked. A nearby Ankur was
 unaffected by these events.

在第二行（第一）单词未受影响之前有空格我不想在那里有空格。

Answer 1

您可以在加入后将其删除：

your_string = ' '.join(newContents).replace('\n ', '\n')
print(your_string)

Answer 2

这是一个足够简单的解决方案：将\n[space]替换为\n。这样，所有空格都保持不变，只更换字符串为\n[space]，换行没有空格

>>> newContents = ['The', 'crazy', 'panda', 'walked', 'to', 'the', 'Maulik', 'and', 'then', 'picked.', 'A', 'nearby', 'Ankur', 'was\n', 'unaffected', 'by', 'these', 'events.\n']
>>> print(' '.join(newContents).replace('\n ', '\n'))
The crazy panda walked to the Maulik and then picked. A nearby Ankur was
unaffected by these events.

Answer 3

您可以使用replace检查换行后的空格：

print(' '.join(newContents).replace('\n ', '\n'))

输出：

The crazy panda walked to the Maulik and then picked. A nearby Ankur was
unaffected by these events.

Answer 4

使用re.sub功能在换行符后立即删除空格：

import re

newContents = ['The', 'crazy', 'panda', 'walked', 'to', 'the', 'Maulik', 'and', 'then', 'picked.', 'A', 'nearby', 'Ankur', 'was\n', 'unaffected', 'by', 'these', 'events.\n']
print(re.sub(r'\n\s+', '\n',' '.join(newContents)))

输出：

The crazy panda walked to the Maulik and then picked. A nearby Ankur was
unaffected by these events.

以上内容还将删除换行符后的多个空格（如果出现）

Answer 5

从每个空格中删除空格：

>>> newContents = ['The', 'crazy', 'panda', 'walked', 'to', 'the', 'Maulik', 'and', 'then', 'picked.', 'A', 'nearby', 'Ankur', 'was\n', 'unaffected', 'by', 'these', 'events.\n']
>>> print(' '.join(item.strip() for item in newContents))
The crazy panda walked to the Maulik and then picked. A nearby Ankur was unaffected by these events.