Question

我明白这个错误意味着什么，但有人可以解释我对这个特定代码的错误吗？基本上，路径= [A，B，C，D]，我只是创建[4] [4]（最终）二维数组，交换相邻的索引。交换从最后一个元素和之前的元素开始，并在循环开始时转到列表的开头。所以最后我得到[[A，B，D，C] [A，C，B，D]，[B，A，C，D]，[D，B，C，A]]

    t = -1
    s = 1
    y = []
    final = []
    path = self.path #path = [A,B,C,D]
    for x in path:
        y.append(path)
        if s < 4:        #Just ensuring to not get out of range
            y[-s],y[-s-1] = y[-s-1],y[-s]
        else:
            y[-1],y[0] = y[0],y[-1]
        final.append(y)
        y = []         # So I won't create multi-dimensional list

错误：列表索引超出范围

Answer 1

因为此处y变为[[A, B, C, D]]而不是[A, B, C, D]。所以它只有一个元素。

Answer 2

这是一段有效且可读的代码：

path= ['A','B','C','D']

final= []
for index in range(len(path)):
    row= path[:] # copy the original list
    row[index-1],row[index]= row[index],row[index-1] # swap 2 elements
    final.insert(0, row) # insert at the start so the order is as expected

print(final)

列表索引超出范围我无法看到

2 个答案: