我想通过两个列表将连接结果写入txt.bz2文件(文件名由代码命名,开头不存在)。喜欢txt文件中的以下表格。
1 a,b,c
0 d,f,g
.......
但是有错误。我的代码如下,请给我提示如何处理它。谢谢!
导入bz2
x = ['a b c', 'd f g', 'h i k', 'k j l']
y = [1, 0, 0, 1]
with bz2.BZ2File("data/result_small.txt.bz2", "w") as bz_file:
for i in range(len(y)):
m = ','.join(x[i].split(' '))
n = str(y[i])+'\t'+m
bz_file.write(n)
错误:
compressed = self._compressor.compress(data)
TypeError: a bytes-like object is required, not 'str'
答案 0 :(得分:1)
使用文件bz2.BZ2File(path)
打开bz2文件。
with bz2.BZ2File("data/result_small.txt.bz2", "rt") as bz_file:
#...
答案 1 :(得分:0)
以文本模式打开文件:
import bz2
x = ['a b c', 'd f g', 'h i k', 'k j l']
y = [1, 0, 0, 1]
with bz2.open("data/result_small.txt.bz2", "wt") as bz_file:
for i in range(len(y)):
m = ','.join(x[i].split(' '))
n = str(y[i]) + '\t' + m
bz_file.write(n + '\n')
更简洁:
import bz2
x = ['a b c', 'd f g', 'h i k', 'k j l']
y = [1, 0, 0, 1]
with bz2.open("data/result_small.txt.bz2", "wt") as bz_file:
for a, b in zip(x, y):
bz_file.write('{}\t{}\n'.format(b, ','.join(a.split())))