Question

我编写解析日志文件的Swift应用程序。日志文件字符串：

substr1 substr2 "substr 3" substr4

我需要获取数组：[substr1, substr2, substr 3, substr4] 但如果我使用类似的东西：

print(stringLine.components(separatedBy: " "))

我得到了：[substr1, substr2, "substr, 3", substr4]。

如何接收阵列：[substr1, substr2, substr 3, substr4]？

Answer 1

其中一种可能的解决方案是使用map：

    let testSting = "substr1 substr2 \"substr3\" substr4"

    let mappedString = testString.components(separatedBy: " ").map({$0.replacingOccurrences(of: "\"", with: "")})

    print(mappedString) //["substr1", "substr2", "substr3", "substr4"]

此问题需要使用正则表达式，但提供了此示例。因此，为了解决您的问题，可以这样做：

var testStingArray  = testSting.replacingOccurrences(of: "\"", with: "").components(separatedBy: " ")

var arr = [String]()

var step = 0

while step < testStingArray.count {
    var current = testStingArray[step]
    var next = step + 1
    if next < testStingArray.count {
        if testStingArray[next].characters.count == 1 {
            current += " " + testStingArray[next]
            testStingArray.remove(at: next)
        }
    }
    arr.append(current)
    step += 1
}

print(arr)//["substr1", "substr2", "substr 3", "substr4"]

Answer 2

或者，您可以根据CharacterSet拆分字符串，然后过滤掉空白事件：

let stringLine = "substr1 substr2 \"substr3\" substr4"
let array = stringLine.components(separatedBy: CharacterSet(charactersIn: "\" ")).filter { !$0.isEmpty }
print (array)

输出：["substr1", "substr2", "substr3", "substr4"]

但如果其中一个'substrings'中有某个"，那么这将无法正常工作，那么该特定子字符串也将被拆分。

Answer 3

你最好使用正则表达式：

let pattern = "([^\\s\"]+|\"[^\"]+\")"
let regex = try! NSRegularExpression(pattern: pattern, options: [])

let line = "substr1 substr2 \"substr 3\" substr4"

let arr = regex.matches(in: line, options: [], range: NSRange(0..<line.utf16.count))
    .map{(line as NSString).substring(with: $0.rangeAt(1)).trimmingCharacters(in: CharacterSet(charactersIn: "\""))}

print(arr) //->["substr1", "substr2", "substr 3", "substr4"]

Answer 4

或者，只需遍历字符并保持引用部分的状态：

0.0.0.0

注意：此代码并未考虑双引号//: Playground - noun: a place where people can play import UIKit extension String { func parse() -> [String] { let delimiter = Character(" ") let quote = Character("\"") var tokens = [String]() var pending = "" var isQuoted = false for character in self.characters { if character == quote { isQuoted = !isQuoted } else if character == delimiter && !isQuoted { tokens.append(pending) pending = "" } else { pending.append(character) } } // Add final token if !pending.isEmpty { tokens.append(pending) } return tokens } } print ("substr1 substr2 \"substr 3\" substr4".parse()) // ["substr1", "substr2", "substr 3", "substr4"] print ("\"substr 1\" substr2 \"substr 3\" substr4".parse()) // ["substr 1", "substr2", "substr 3", "substr4"] print ("a b c d".parse()) // ["a", "b", "c", "d"]可能用于转义单引号。但我不知道你的情况是否有可能。

https://tburette.github.io/blog/2014/05/25/so-you-want-to-write-your-own-CSV-code/

Swift将字符串拆分为数组并排除

4 个答案: