我正在使用SQL Server 2014.我有以下代码来创建触发器(它插入数据):
CREATE TRIGGER [dbo].[INSERT_TR_LAB_TESTS_RESULTS]
ON [dbo].[TRANSACTIONS_TBL]
AFTER INSERT, UPDATE, DELETE
AS
DECLARE @SERVICE_CODE INT
DECLARE @INVOICE_NO INT
DECLARE @PATIENT_TYPE_ID INT
DECLARE @INSURANCE_COMPANY_ID INT
DECLARE @INSURANCE_CARD_NO VARCHAR(50)
DECLARE @SPONSER_TYPE_ID INT
DECLARE @QTY_OF_SERVICES INT
DECLARE @PATIENT_NAME_ID INT
DECLARE @LAB_TEST_CATEGORY_ID INT
DECLARE @LAB_TEST_NAME nvarchar(100)
DECLARE @LAB_TEST_RESULT VARCHAR(100)
DECLARE @RESULT_REFERENCE_VALUE nvarchar(70)
DECLARE @TEST_UNIT nvarchar(50)
INSERT INTO LAB_TESTS_RESULTS (SERVICE_CODE, INVOICE_NO, PATIENT_TYPE_ID,
INSURANCE_COMPANY_ID, INSURANCE_CARD_NO,
SPONSER_TYPE_ID, QTY_OF_SERVICES, PATIENT_NAME_ID,
LAB_TEST_CATEGORY_ID, LAB_TEST_NAME,
LAB_TEST_RESULT, RESULT_REFERENCE_VALUE, TEST_UNIT)
SELECT
t1.SERVICE_CODE, t1.INVOICE_NO, t1.PATIENT_TYPE_ID,
t1.INSURANCE_COMPANY_ID, t1.INSURANCE_CARD_NO,
t1.SPONSER_TYPE_ID, t1.QTY_OF_SERVICES, t1.PATIENT_NAME_ID,
t2.LAB_TEST_CATEGORY_ID, t2.LAB_TEST_NAME,
t2.LAB_TEST_RESULT, t2.RESULT_REFERENCE_VALUE, t2.TEST_UNIT
FROM
TRANSACTIONS_TBL t1
CROSS JOIN
LAB_TESTS_NAMES_TBL t2
WHERE
t1.SERVICE_CODE = t2.SERVICE_CODE
GO
如果仅在尚不存在时插入值,否则更新它们?
答案 0 :(得分:0)
假设您的表格的密钥为SERVICE_CODE
,请按照下一种方法操作: -
IF EXISTS (SELECT * FROM LAB_TESTS_RESULTS WHERE SERVICE_CODE = @SERVICE_CODE)
BEGIN
-- Put your update statement here
End
Else
BEGIN
-- Put your Insert statement here
End
完整代码: -
CREATE TRIGGER [dbo].[INSERT_TR_LAB_TESTS_RESULTS]
ON [dbo].[TRANSACTIONS_TBL]
AFTER INSERT, UPDATE, DELETE
AS
DECLARE @SERVICE_CODE INT
DECLARE @INVOICE_NO INT
DECLARE @PATIENT_TYPE_ID INT
DECLARE @INSURANCE_COMPANY_ID INT
DECLARE @INSURANCE_CARD_NO VARCHAR(50)
DECLARE @SPONSER_TYPE_ID INT
DECLARE @QTY_OF_SERVICES INT
DECLARE @PATIENT_NAME_ID INT
DECLARE @LAB_TEST_CATEGORY_ID INT
DECLARE @LAB_TEST_NAME nvarchar(100)
DECLARE @LAB_TEST_RESULT VARCHAR(100)
DECLARE @RESULT_REFERENCE_VALUE nvarchar(70)
DECLARE @TEST_UNIT nvarchar(50)
IF EXISTS (SELECT * FROM LAB_TESTS_RESULTS WHERE SERVICE_CODE = @SERVICE_CODE)
BEGIN
Update LAB_TESTS_RESULTS
Set
INVOICE_NO = @INVOICE_NO,
PATIENT_TYPE_ID = @PATIENT_TYPE_ID ,
INSURANCE_COMPANY_ID = @INSURANCE_COMPANY_ID,
INSURANCE_CARD_NO = @INSURANCE_CARD_NO,
SPONSER_TYPE_ID = @SPONSER_TYPE_ID,
QTY_OF_SERVICES = @QTY_OF_SERVICES,
PATIENT_NAME_ID = @PATIENT_NAME_ID,
LAB_TEST_CATEGORY_ID = @LAB_TEST_CATEGORY_ID,
LAB_TEST_NAME = @LAB_TEST_NAME,
LAB_TEST_RESULT = @LAB_TEST_RESULT,
RESULT_REFERENCE_VALUE = @RESULT_REFERENCE_VALUE,
TEST_UNIT = @TEST_UNIT
Where
SERVICE_CODE = @SERVICE_CODE
END
ELSE
BEGIN
INSERT INTO LAB_TESTS_RESULTS (SERVICE_CODE, INVOICE_NO, PATIENT_TYPE_ID, INSURANCE_COMPANY_ID, INSURANCE_CARD_NO, SPONSER_TYPE_ID, QTY_OF_SERVICES, PATIENT_NAME_ID, LAB_TEST_CATEGORY_ID, LAB_TEST_NAME, LAB_TEST_RESULT, RESULT_REFERENCE_VALUE, TEST_UNIT)
SELECT
t1.SERVICE_CODE, t1.INVOICE_NO, t1.PATIENT_TYPE_ID,
t1.INSURANCE_COMPANY_ID, t1.INSURANCE_CARD_NO,
t1.SPONSER_TYPE_ID, t1.QTY_OF_SERVICES, t1.PATIENT_NAME_ID,
t2.LAB_TEST_CATEGORY_ID, t2.LAB_TEST_NAME,
t2.LAB_TEST_RESULT, t2.RESULT_REFERENCE_VALUE, t2.TEST_UNIT
FROM
TRANSACTIONS_TBL t1
CROSS JOIN
LAB_TESTS_NAMES_TBL t2
WHERE
t1.SERVICE_CODE = t2.SERVICE_CODE
END
GO