为什么这段代码不起作用？我应该分离价值观？

Question

我有一个大的CSV文件，我试图将其制作成较小的子列表。

唯一的问题是它没有做它应该做的事情......或者至少正确地分离数据只有一些东西被正确分开

我的问题：我有一个CSV文件，其数据深度在90到3米之间，而且这些数据会像这样来回传递。我正在使用最新的python。

每次数字再次增加时，我想将其分开。

离。 （深度）88,77,50,20,5,90,76,54,34,15,8,4,81,74,62,51,49,30,22,10,8 ......依此类推。它保持在90到3之间，依此类推。

我想要做的是每次在90到3之间分离数据。一旦它被分开，我想获取该列表中的最后和第一个值。像这样前。 88,77,50,20,5（此处分开），90,76,54,34,15,8,4（此处分开）81,74,62,51,49,30,22,10,8分开在这里）......等等。

这是我的代码：

#two sets of data that you test with.
m = ['9.90203', '9.79947', '9.66876', '9.54503', '9.42167', '9.2977', '9.17321', '9.05162', '8.11487', '8.038', '7.96111', '7.85746', '7.72701', '7.59709', '7.46781', '7.34127', '7.21842', '7.09548', '6.96798', '6.57355', '6.444', '6.32245', '6.23818', '6.15369', '6.04973', '4.63443', '4.49823', '4.36232', '4.21442', '4.0642', '26.5645', '26.4945', '26.4232', '26.3592', '26.2948', '23.418', '23.3667', '23.2756', '23.1856', '22.1849', '22.0822', '22.0191', '21.9671', '21.9154', '21.8641', '20.436', '20.3865', '20.3364', '20.2083', '20.0915', '19.9758', '19.8601', '19.7446', '19.6317', '18.1383', '17.9834', '17.8271', '17.7529', '17.6949', '17.6317', '17.5675', '17.4362', '16.581', '16.4745', '16.378', '16.2562', '16.1471', '16.0222', '15.89', '14.9752', '14.8725', '14.7666', '14.6234', '14.469', '14.3148', '13.7696', '13.6465', '13.5363', '13.4712', '13.4069', '13.3421', '13.2732', '13.1375', '13.0014', '12.4809', '12.3585', '12.2339', '12.121', '12.0116', '11.901', '11.7906', '11.6645', '11.5278', '11.3931', '11.2551', '11.1211', '10.993', '10.8501', '10.7205', '10.6026', '10.4992', '10.3952']
l = ['8.18142', '8.11846', '8.05988', '59.4627', '59.3455', '59.2296', '58.4541', '58.3302', '58.2265', '58.1239', '58.0314', '57.9405', '57.8496', '57.7514', '57.6746', '57.6098', '57.5414', '57.4722', '57.3517', '57.2151', '57.0934', '56.9704', '56.8361', '56.6993', '56.564', '56.4287', '56.3106', '56.2', '56.0877', '55.9782', '55.8869', '55.8223', '55.7578', '55.6933', '55.605', '55.4949', '55.3858', '55.2761', '55.1612', '55.0097', '54.8786', '54.7385', '54.6315', '54.5282', '54.4292', '54.327', '54.2217', '54.1127', '54.0037', '53.8938', '53.7695', '53.6271', '53.4857', '53.3437', '53.2254', '53.1712', '53.12', '53.0679', '53.0102', '52.9126', '52.8148', '52.7182', '52.6207', '52.491', '52.3561', '52.2267', '52.0908', '51.9405', '51.7786', '51.6421', '51.5043', '51.4063', '51.3087', '51.2117', '51.1141', '51.0304', '50.9446', '50.8577', '50.7744', '50.6716', '50.5655', '50.4625', '50.3598', '50.2569', '50.153', '50.0494', '49.9461', '49.8308', '49.7058', '49.582', '49.4583', '49.3473', '49.251', '49.1533', '49.0561', '48.953', '48.83', '48.7064', '48.5812', '48.4635', '48.3852', '48.2998', '48.2219', '48.1428', '48.0327', '47.9221', '47.8114', '47.7007', '47.5964', '47.4905', '47.3875', '47.2847', '47.1595', '47.0424', '46.9264']

group =0
temp = []
splited_list = {}
lengh = len(l)

for i in range(lengh):
    if not i == lengh-1:
        if l[i] > l[i+1]:
            temp.append(l[i])
        else:
            temp.append(l[i])
            group +=1
            splited_list.update({str(group):temp})
            temp = []
    else:
        if l[i] < l[-2]:
           temp.append(l[i])
           group +=1
           splited_list.update({str(group):temp})
           break
        else:
            group +=1
            splited_list.update({str(group):[l[i]]})
            break

print (splited_list)

这是我的输出：

  

{＆＃39; 1＆＃39;：[＆＃39; 8.18142＆＃39;，＆＃39; 8.11846＆＃39;，＆＃39; 8.05988＆＃39;，＆＃39; 59.4627＆ ＃39;，＆＃39; 59.3455＆＃39;，＆＃39; 59.2296＆＃39;，＆＃39; 58.4541＆＃39;，＆＃39; 58.3302＆＃39;，＆＃39; 58.2265＆ ＃39;，＆＃39; 58.1239＆＃39;，＆＃39; 58.0314＆＃39;，＆＃39; 57.9405＆＃39;，＆＃39; 57.8496＆＃39;，＆＃39; 57.7514＆ ＃39;，＆＃39; 57.6746＆＃39;，＆＃39; 57.6098＆＃39;，＆＃39; 57.5414＆＃39;，＆＃39; 57.4722＆＃39;，＆＃39; 57.3517＆ ＃39;，＆＃39; 57.2151＆＃39;，＆＃39; 57.0934＆＃39;，＆＃39; 56.9704＆＃39;，＆＃39; 56.8361＆＃39;，＆＃39; 56.6993＆ ＃39;，＆＃39; 56.564＆＃39;，＆＃39; 56.4287＆＃39;，＆＃39; 56.3106＆＃39;，＆＃39; 56.2＆＃39;，＆＃39; 56.0877＆ ＃39;，＆＃39; 55.9782＆＃39;，＆＃39; 55.8869＆＃39;，＆＃39; 55.8223＆＃39;，＆＃39; 55.7578＆＃39;，＆＃39; 55.6933＆ ＃39;，＆＃39; 55.605＆＃39;，＆＃39; 55.4949＆＃39;，＆＃39; 55.3858＆＃39;，＆＃39; 55.2761＆＃39;，＆＃39; 55.1612＆ ＃39;，＆＃39; 55.0097＆＃39;，＆＃39; 54.8786＆＃39;，＆＃39; 54.7385＆＃39;，＆＃39; 54.6315＆＃39;，＆＃39; 54.5282＆ ＃39;，＆＃39; 54.4292＆＃39;，＆＃39; 54.327＆＃39;，＆＃39; 54.2217＆＃39;，＆＃39; 54.1127＆＃39;，＆＃39; 54.0037＆ ＃39;，＆＃39; 53.8938＆＃39;，＆＃39; 53.7695＆＃39;，＆＃39; 53.6271＆＃39;， ＆＃39; 53.4857＆＃39;，＆＃39; 53.3437＆＃39;，＆＃39; 53.2254＆＃39;，＆＃39; 53.1712＆＃39;，＆＃39; 53.12＆＃39;， ＆＃39; 53.0679＆＃39;，＆＃39; 53.0102＆＃39;，＆＃39; 52.9126＆＃39;，＆＃39; 52.8148＆＃39;，＆＃39; 52.7182＆＃39;， ＆＃;;;;;;;;;;;;;;; ＆＃39; 51.9405＆＃39;，＆＃39; 51.7786＆＃39;，＆＃39; 51.6421＆＃39;，＆＃39; 51.5043＆＃39;，＆＃39; 51.4063＆＃39;， ＆＃39; 51.3087＆＃39;，＆＃39; 51.2117＆＃39;，＆＃39; 51.1141＆＃39;，＆＃39; 51.0304＆＃39;，＆＃39; 50.9446＆＃39;， ＆＃39; 50.8577＆＃39;，＆＃39; 50.7744＆＃39;，＆＃39; 50.6716＆＃39;，＆＃39; 50.5655＆＃39;，＆＃39; 50.4625＆＃39;， ＆＃39; 50.3598＆＃39;，＆＃39; 50.2569＆＃39;，＆＃39; 50.153＆＃39;，＆＃39; 50.0494＆＃39;，＆＃39; 49.9461＆＃39;， ＆＃39; 49.8308＆＃39;，＆＃39; 49.7058＆＃39;，＆＃39; 49.582＆＃39;，＆＃39; 49.4583＆＃39;，＆＃39; 49.3473＆＃39;， ＆＃39; 49.251＆＃39;，＆＃39; 49.1533＆＃39;，＆＃39; 49.0561＆＃39;，＆＃39; 48.953＆＃39;，＆＃39; 48.83＆＃39;， ＆＃;;;;;;;;;;;;;;;;;;;;; ＆＃39; 48.2219＆＃39;，＆＃39; 48.1428＆＃39;，＆＃39; 48.0327＆＃39;，＆＃ 39; 47.9221＆＃39;，＆＃39; 47.8114＆＃39;，＆＃39; 47.7007＆＃39;，＆＃39; 47.5964＆＃39;，＆＃39; 47.4905＆＃39;，＆＃ 39; 47.3875＆＃39;，＆＃39; 47.2847＆＃39;，＆＃39; 47.1595＆＃39;，＆＃39; 47.0424＆＃39;，＆＃39; 46.9264＆＃39;]} < / p>

这是我想要的输出：

  

{＆＃39; 1＆＃39;：[＆＃39; 8.18142＆＃39;，＆＃39; 8.11846＆＃39;，＆＃39; 8.05988＆＃39;]，＆＃39; 2＆ ＃39;：[＆＃39; 59.4627＆＃39;，＆＃39; 59.3455＆＃39;，＆＃39; 59.2296＆＃39;，＆＃39; 58.4541＆＃39;，＆＃39; 58.3302 ＆＃39;，＆＃39; 58.2265＆＃39;，＆＃39; 58.1239＆＃39;，＆＃39; 58.0314＆＃39;，＆＃39; 57.9405＆＃39;，＆＃39; 57.8496 ＆＃39;，＆＃39; 57.7514＆＃39;，＆＃39; 57.6746＆＃39;，＆＃39; 57.6098＆＃39;，＆＃39; 57.5414＆＃39;，＆＃39; 57.4722 ＆＃39;，＆＃39; 57.3517＆＃39;，＆＃39; 57.2151＆＃39;，＆＃39; 57.0934＆＃39;，＆＃39; 56.9704＆＃39;，＆＃39; 56.8361 ＆＃39;，＆＃39; 56.6993＆＃39;，＆＃39; 56.564＆＃39;，＆＃39; 56.4287＆＃39;，＆＃39; 56.3106＆＃39;，＆＃39; 56.2 ＆＃39;，＆＃39; 56.0877＆＃39;，＆＃39; 55.9782＆＃39;，＆＃39; 55.8869＆＃39;，＆＃39; 55.8223＆＃39;，＆＃39; 55.7578 ＆＃39;，＆＃39; 55.6933＆＃39;，＆＃39; 55.605＆＃39;，＆＃39; 55.4949＆＃39;，＆＃39; 55.3858＆＃39;，＆＃39; 55.2761 ＆＃39;，＆＃39; 55.1612＆＃39;，＆＃39; 55.0097＆＃39;，＆＃39; 54.8786＆＃39;，＆＃39; 54.7385＆＃39;，＆＃39; 54.6315 ＆＃39;，＆＃39; 54.5282＆＃39;，＆＃39; 54.4292＆＃39;，＆＃39; 54.327＆＃39;，＆＃39; 54.2217＆＃39;，＆＃39; 54.1127 ＆＃39;，＆＃39; 54.0037＆＃39;，＆＃39; 53.8938＆＃39;，＆＃39; 53.7695＆＃39;，＆＃39 ; 53.6271＆＃39;，＆＃39; 53.4857＆＃39;，＆＃39; 53.3437＆＃39;，＆＃39; 53.2254＆＃39;，＆＃39; 53.1712＆＃39;，＆＃39 ; 53.12＆＃39;，＆＃39; 53.0679＆＃39;，＆＃39; 53.0102＆＃39;，＆＃39; 52.9126＆＃39;，＆＃39; 52.8148＆＃39;，＆＃39 ; 52.7182＆＃39;，＆＃39; 52.6207＆＃39;，＆＃39; 52.491＆＃39;，＆＃39; 52.3561＆＃39;，＆＃39; 52.2267＆＃39;，＆＃39 ; 52.0908＆＃39;，＆＃39; 51.9405＆＃39;，＆＃39; 51.7786＆＃39;，＆＃39; 51.6421＆＃39;，＆＃39; 51.5043＆＃39;，＆＃39 ; 51.4063＆＃39;，＆＃39; 51.3087＆＃39;，＆＃39; 51.2117＆＃39;，＆＃39; 51.1141＆＃39;，＆＃39; 51.0304＆＃39;，＆＃39 ; 50.9446＆＃39;，＆＃39; 50.8577＆＃39;，＆＃39; 50.7744＆＃39;，＆＃39; 50.6716＆＃39;，＆＃39; 50.5655＆＃39;，＆＃39 ; 50.4625＆＃39;，＆＃39; 50.3598＆＃39;，＆＃39; 50.2569＆＃39;，＆＃39; 50.153＆＃39;，＆＃39; 50.0494＆＃39;，＆＃39 ; 49.9461＆＃39;，＆＃39; 49.8308＆＃39;，＆＃39; 49.7058＆＃39;，＆＃39; 49.582＆＃39;，＆＃39; 49.4583＆＃39;，＆＃39 ; 49.3473＆＃39;，＆＃39; 49.251＆＃39;，＆＃39; 49.1533＆＃39;，＆＃39; 49.0561＆＃39;，＆＃39; 48.953＆＃39;，＆＃39 ; 48.83＆＃39;，＆＃39; 48.7064＆＃39;，＆＃39; 48.5812＆＃39;，＆＃39; 48.4635＆＃39;，＆＃39; 48.3852＆＃39;，＆＃39 ; 48.2998＆＃39;，＆＃39; 48.2219＆＃39;，＆＃39; 48.1428＆＃39;，＆＃39; 4 8.0327＆＃39;，＆＃39; 47.9221＆＃39;，＆＃39; 47.8114＆＃39;，＆＃39; 47.7007＆＃39;，＆＃39; 47.5964＆＃39;，＆＃39; 47.4905＆＃39;，＆＃39; 47.3875＆＃39;，＆＃39; 47.2847＆＃39;，＆＃39; 47.1595＆＃39;，＆＃39; 47.0424＆＃39;，＆＃39; 46.9264＆＃39;]}

Answer 1

我认为你过度复杂了。请记住，要进行比较，首先要将字符串转换为浮点数。而且，没有必要通过其索引来引用每个点;您可以直接迭代list对象。 另外，如上所述，使用由整数键入的字典有点不寻常，请考虑使用列表列表。

points = ['9.90203', '9.79947', '9.66876', '9.54503', '9.42167', '9.2977', '9.17321', '9.05162', '8.11487', '8.038',
          '7.96111', '7.85746', '7.72701', '7.59709', '7.46781', '7.34127', '7.21842', '7.09548', '6.96798', '6.57355',
          '6.444', '6.32245', '6.23818', '6.15369', '6.04973', '4.63443', '4.49823', '4.36232', '4.21442', '4.0642',
          '26.5645', '26.4945', '26.4232', '26.3592', '26.2948', '23.418', '23.3667', '23.2756', '23.1856', '22.1849',
          '22.0822', '22.0191', '21.9671', '21.9154', '21.8641', '20.436', '20.3865', '20.3364', '20.2083', '20.0915',
          '19.9758', '19.8601', '19.7446', '19.6317', '18.1383', '17.9834', '17.8271', '17.7529', '17.6949', '17.6317',
          '17.5675', '17.4362', '16.581', '16.4745', '16.378', '16.2562', '16.1471', '16.0222', '15.89', '14.9752',
          '14.8725', '14.7666', '14.6234', '14.469', '14.3148', '13.7696', '13.6465', '13.5363', '13.4712', '13.4069',
          '13.3421', '13.2732', '13.1375', '13.0014', '12.4809', '12.3585', '12.2339', '12.121', '12.0116', '11.901',
          '11.7906', '11.6645', '11.5278', '11.3931', '11.2551', '11.1211', '10.993', '10.8501', '10.7205', '10.6026',
          '10.4992', '10.3952']

data = dict()
idx = 1
last_point = float(points[0])
subset = [points[0]]
for point in points[1:]:
    num_point = float(point)
    if num_point > last_point:
        data[idx] = subset
        subset = [point]
        idx += 1
    else:
        subset.append(point)
    last_point = num_point

data[idx] = subset

Answer 2

您可以尝试以下操作：

l = map(float, l)
results = [[ l[0] ]]

for i in l[1:]:
    if i>results[-1][-1]:
        results.append([i])
    else:
        results[-1].append(i)

这将为您提供列表清单。如果您真的想要字典，可以尝试：

resultsDict = {i:m for i, m in enumerate(results)}

或稍微缩短一下：

resultsDict = dict(enumerate(results))

我更喜欢上一个，因为它更具可读性......

如果您确实需要保留字符串，可以将比较i>results[-1][-1]更改为float(i)>float(results[-1][-1])，并删除最初的map。