HTTP条纹请求未经过[Swift]

Question

我目前正将我的IOS应用与后端相关联以处理Stripe付款。我使用FileZilla来托管文件，使用cSpan来托管服务器。这是我的快速代码：

 let task = session.dataTask(with: request as URLRequest, completionHandler: {data, response, errorD -> Void in
        if errorD == nil {
            print("got response")

            do {
                let jsonResult: NSDictionary? = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary



                let jsonComp = jsonResult?.value(forKey: "completion") as! String
                print(jsonComp)
            } catch {
                print(errorD?.localizedDescription)
                // ERROR OCCURS HERE 
            }



            //let jsonResult: Any! = JSONSerialization.jsonObject(with: data!, options: .mutableContainers)
           // print(jsonResult)

            } else {
            print("error")
        }
    }) task.resume()

这是我的FileZilla目录的屏幕截图：

（我刚刚意识到图片实际上没有在Payments目录中显示文件'token.php'，但它就在那里。）

正如您所看到的，我正确地进入正确的目录以访问该文件，并执行正确的方法来完成HTTP请求。然而，奇怪的是它会在'catch'之后总是导致错误，但是当我尝试打印错误的本地化描述时它将显示nil。这是token.php

中的php代码

<?php

require_once('stripe-php/init.php');

\Stripe\Stripe::setApiKey("sk_test_eRFc0VoIi7mo7zBuArrznB5a");

// Get the credit card details submitted by the form

$token = $_POST['stripeToken'];

$amount = $_POST['amount'];

$type = $_POST['type'];

$name = $_POST['name'];

// Create the charge on Stripe's servers - this will charge the user's card

try {

$charge = \Stripe\Charge::create(array(

"amount" => $amount,

"currency" => "usd",

"source" => $token,)

);



//email the purcahse and code info to your email

mail("willcohen2000@gmail.com","Purchase done","amount: $amount , type: $type, name: $name");

// create a json output with completion variable, (this will be read from the ios app as response)

$json = array(

'completion' => 'done'

);

echo json_encode($json);

} catch(\Stripe\Error\Card $e) {

// The card has been declined

$errorMessage = $e->getMessage();

$json = array(

'completion' => $getMessage()

);

echo json_encode($json);

}

?>

由于可能有点明显，我对后端工作相对缺乏经验，所以任何解释或指向正确的方向都将受到高度赞赏。感谢。