在getInputStream
和getErrorStream
HttpsURLConnection connection = (HttpsURLConnection) url.openConnection();
BufferedReader bufferedReader;
if(connection.getResponseCode() == 200) {
bufferedReader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
} else {
bufferedReader = new BufferedReader(new InputStreamReader(connection.getErrorStream()));
}
String line;
StringBuilder result = new StringBuilder();
while((line = bufferedReader.readLine()) != null) {result.append(line);}
bufferedReader.close();
if(connection.getResponseCode() != 200) {
throw new Gson().fromJson(result.toString(), FooException.class);
} else {
return new Gson().fromJson(result.toString(), Foo.class);
}
答案 0 :(得分:1)
如果我理解了您的问题,那么您可以使用三元运算符? :
在BufferedReader
中构建try-with-resources
。另外,我将responseCode
保存到局部变量。像,
StringBuilder result = new StringBuilder();
int responseCode = connection.getResponseCode();
try (BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(
responseCode == 200 ? connection.getInputStream()
: connection.getErrorStream()))) {
String line;
while ((line = bufferedReader.readLine()) != null) {
result.append(line);
}
}
if (responseCode != 200) {
throw new Gson().fromJson(result.toString(), FooException.class);
} else {
return new Gson().fromJson(result.toString(), Foo.class);
}