我是PHP和MySQL的新手,我想问一下如何检查我的数据库中是否存在用户名?使用mysqli_num_rows检查我的变量$ userchecker和我的if语句。我知道这是错的,但我不知道如何做对。
if(isset($_POST['submit'])){
$username = trim($_POST['username']);
$password = trim($_POST['password']);
$username = mysqli_escape_string($con,$username);
$password = mysqli_escape_string($con,$password);
//Database connection
$con = mysqli_connect('localhost','root','Jarious','register_and_login');
$error = false;
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
$userchecker = mysqli_query($con,"SELECT * FROM users WHERE user_name = '$username'");
if(empty($username) || mb_strlen($username) < 5){
echo "Username is too short or empty." . '<br />';
$error = true;
}
if(empty($password) || mb_strlen($password) < 5){
echo 'Password is too short or empty. <br />';
$error = true;
}
if(mysqli_num_rows($userchecker) > 1){
echo 'Username is already taken.';
$еrror = true;
}
if(!$error){
$password = md5($password);
$query = "INSERT INTO users(user_name,pass_word) VALUES ('$username', '$password')";
$useradd = mysqli_query($con,$query);
}
}
答案 0 :(得分:0)
你的代码非常庞大。所有想要在这里实现的东西都已在(PHP)框架中定义。显然,下面的SQL应该很容易做到。最初来自评论:
SELECT count(*) FROM users WHERE user_name = '$username'
答案 1 :(得分:-3)
<?
$n=$_POSTE['d1'];
$p=$_POSTE['t1'];
$c=mysql_connect('localhost','root','');
$b=mysql_select_db('lica');
$r1='SELECT * FORM user WHERE ($name='iheb')';
$r=mysql_query($r1);
if(mysql_num_rows($r)==0)
echo'n''not existe ';
else
echo 'exist';
我认为这项工作