Question

我无法获得数组密钥。

例如：我创建了包含信息的数组

z[condition1] = (1/(sigma*np.sqrt(2*np.pi) ))*np.e**(-0.5*((x[condition1]-y[condition1]+Q1-u)/sigma)**2. IndexError: index 1 is out of bounds for axis 1 with size 1.等等。

如果我只知道人的标识符 - 525359，我怎么能找到数组的关键字？我试过这段代码

from matplotlib.ticker import LinearLocator, FormatStrFormatter import matplotlib.pyplot as plt import sympy as sp from sympy import * import numpy as np from scipy.stats import lognorm, beta from quantecon import LAE from sympy import symbols q= symbols('q') ## == Define parameters == # a_sigma = 0.4 psi_0 = beta(5, 5, scale=0.5) # Initial distribution phi = lognorm(a_sigma) def p(x,y): u=80 sigma=30 b=0.2 Q=80 Q1=Q*(1-b) Q2=Q*(1+b) z = np.zeros_like(x, dtype=float) # Condition 1 indexes all elements where subformula 1 is valid condition1 = np.logical_and(y>0.0, x >=y-Q1) z[condition1] = (1/(sigma*np.sqrt(2*np.pi) ))*np.e**(-0.5*((x[condition1]-y[condition1]+Q1-u)/sigma)**2) condition2 = np.logical_and(y<0.0, x >=y-Q2) z[condition2] = (1/(sigma*np.sqrt(2*np.pi) ))*np.e**(-0.5*((x[condition2]-y[condition2]+Q2-u)/sigma)**2) condition3 = np.logical_and(y==0.0, x >=-Q1) #print(-0.5*((k_prime[condition3] + q - u))**2) j=-0.5*((x[condition3] + q - u))**2 K=[] for elem in j: print(elem) K.append(1/(sigma*sqrt(2*pi) )*sp.integrate(sp.exp(elem),(q,Q1,Q2))) #z[condition3] = K return z n = 10000 # Number of observations at each date t T = 30 # Compute density of k_t at 1,...,T+1 # == Generate matrix s.t. t-th column is n observations of k_t == # k = np.empty((n, T)) A = phi.rvs((n, T)) k[:, 0] = psi_0.rvs(n) # Draw first column from initial distribution for t in range(T-1): k[:, t+1] = k[:, t]+ A[:, t] # == Generate T instances of LAE using this data, one for each date t == # laes = [LAE(p, k[:, t]) for t in range(T)] # == Plot == # fig, ax = plt.subplots() ygrid = np.linspace(0.01, 4.0, 200) greys = [str(g) for g in np.linspace(0.0, 0.8, T)] greys.reverse() for psi, g in zip(laes, greys): ax.plot(ygrid, psi(ygrid), color=g, lw=2, alpha=0.6) ax.set_xlabel('capital') title = r'Density of $k_1$ (lighter) to $k_T$ (darker) for $T={}$' ax.set_title(title.format(T)) plt.show()

但它不起作用。

也许我需要尝试像HTML一样创建模式属性？

Answer 1

array_search仅返回值中具有完全匹配的数组条目。

最好的选择是根据您想要匹配的标识符重新键入数组，以便更轻松地过滤。

第二个最佳选择可能是使用preg_grep，它可以通过数组条目搜索正则表达式。见https://secure.php.net/manual/en/function.preg-grep.php

Answer 2

这是一个基于正则表达式获取键的示例，比如它返回与值中的ee匹配的元素的键。

$colors = array("red", "green", "blue", "yellow"); 

$key=0;
foreach ($colors as $value) {
    if (preg_match("*ee*", $value)) {
                       echo $value." has key = ".$key."<br>";
               break;
      } else {
          $key++;
      }

}

此代码的输出是

green has key = 1

数组中的Array_search查询

2 个答案: