Question

{
  "adult": false,
  "budget": 17000000,
  "crew": [
    {
      "credit_id": {},
      "department": "Directing",
      "id": 40223,
      "job": "Director",
      "name": "Joe Carnahan",
      "profile_path": "/5YPrZ1JprLwtU4tn5DG0wqLjsAT.jpg"
    },
    {
      "credit_id": "55444d6bc3a368573b0008ba",
      "department": "Writing",
      "id": 40223,
      "job": "Writer",
      "name": "Joe Carnahan",
      "profile_path": "/5YPrZ1JprLwtU4tn5DG0wqLjsAT.jpg"
    },
    {
      "credit_id": "52fe4482c3a36847f809a3ed",
      "department": "Production",
      "id": 2236,
      "job": "Producer",
      "name": "Tim Bevan",
      "profile_path": "/f7o93O1KocuLwIrSa7KqyL1sWaT.jpg"
    }
}

嗨！这是tmdb php api的tmdb示例输出。例如，如何以jquery获取Director名称？船员输出的顺序是随机的。

Answer 1

通常，当您在数组中搜索某些内容时，您希望迭代数组直到找到它。无论您使用的是jQuery还是纯JavaScript或任何其他具有数组的语言，都是一样的。

在您的情况下，您希望搜索属性job等于字符串"Director"的对象。

找到后，您希望从该对象返回属性name。

您可以使用for循环执行此操作：

function findDirectorName(data) {
  for (let i = 0; i < data.crew.length; i++) {
    let crewMember = data.crew[i];
    if (crewMember.job === 'Director') {
      return crewMember.name;
    }
  }
}

或许是一个while循环：

function findDirectorName(data) {
  let i = 0;
  while (i < data.crew.length) {
    let crewMember = data.crew[i];
    if (crewMember.job === 'Director') {
      return crewMember.name;
    }
    i++;
  }
}

使用内置方法Array.prototype.find和箭头功能，您可以将代码简化为：

function findDirectorName(data) {
  let director = data.crew.find(crewMember => crewMember.job === 'Director');
  return director ? director.name : undefined;
}

Answer 2

试试这个：

var aMovie = {
  "adult": false,
  "budget": 17000000,
  "crew": [
    {
      "credit_id": {},
      "department": "Directing",
      "id": 40223,
      "job": "Director",
      "name": "Joe Carnahan",
      "profile_path": "/5YPrZ1JprLwtU4tn5DG0wqLjsAT.jpg"
    },
    {
      "credit_id": "55444d6bc3a368573b0008ba",
      "department": "Writing",
      "id": 40223,
      "job": "Writer",
      "name": "Joe Carnahan",
      "profile_path": "/5YPrZ1JprLwtU4tn5DG0wqLjsAT.jpg"
    },
    {
      "credit_id": "52fe4482c3a36847f809a3ed",
      "department": "Production",
      "id": 2236,
      "job": "Producer",
      "name": "Tim Bevan",
      "profile_path": "/f7o93O1KocuLwIrSa7KqyL1sWaT.jpg"
    }]
};

var findDirector = function(aMovie){
  if( !aMovie.crew || aMovie.crew.length==0 ) return "";
  
  var director = aMovie.crew.find( function(member){
      return member.job.toLowerCase() == 'director';
  });
  return director.name;
};

alert(findDirector(aMovie));

Answer 3

我喜欢使用 some() 。

aMovie.crew.some(function(member) {

    var job = member.job.toLowerCase();

    if(job == "director") return member;

}

在JSON对象中查找特定值

3 个答案: