Question

让我们说我有一个像这样的Python字符串：

Some first text:  2342
Another line here:  284
Maybe third line: 458
And forth line: 199

我想从这个字符串创建4个整数变量，使得var =（第1行中的数字）。并且var2 =（第2行中的数字）..依此类推。

怎么可能？

Answer 1

您可以将所有数字存储在数组中：

application-logger.xml

输出：

<configuration>
    <appender name="FILE" class="ch.qos.logback.core.rolling.RollingFileAppender">
        <file>logs/application.log</file>
        <rollingPolicy class="ch.qos.logback.core.rolling.TimeBasedRollingPolicy">
            <!-- Daily rollover with compression -->
            <fileNamePattern>logs/application-log-%d{yyyy-MM-dd}.gz</fileNamePattern>
            <!-- keep 30 days worth of history -->
            <maxHistory>30</maxHistory>
        </rollingPolicy>
        <encoder>
            <pattern>%date{yyyy-MM-dd HH:mm:ss ZZZZ} - [%level] - from %logger in %thread %n%message%n%xException%n
            </pattern>
        </encoder>
    </appender>

    <appender name="FILE-ASYNC" class="ch.qos.logback.classic.AsyncAppender">
        <appender-ref ref="FILE"/>
        <queueSize>1024</queueSize>
        <discardingThreshold>0</discardingThreshold>
    </appender>

    <appender name="LOGSTASH" class="com.cwbase.logback.RedisAppender">
        <source>play-core</source>
        <host>[HIDDEN]</host>
        <port>6379</port>
        <tags>prod</tags>
        <key>logstash</key>
    </appender>

    <appender name="LOGSTASH-ASYNC" class="ch.qos.logback.classic.AsyncAppender">
        <appender-ref ref="LOGSTASH"/>
        <queueSize>1024</queueSize>
        <discardingThreshold>0</discardingThreshold>
    </appender>

    <appender name="SENTRY" class="com.getsentry.raven.logback.SentryAppender">
        <dsn>[HIDDEN]/dsn>
        <tags>env:production</tags>
    </appender>

    <appender name="SENTRY-ASYNC" class="ch.qos.logback.classic.AsyncAppender">
        <appender-ref ref="SENTRY"/>
        <queueSize>1024</queueSize>
        <discardingThreshold>0</discardingThreshold>
        <filter class="ch.qos.logback.classic.filter.LevelFilter">
            <level>ERROR</level>
            <onMismatch>DENY</onMismatch>
        </filter>
    </appender>

    <appender name="ACCESS_FILE" class="ch.qos.logback.core.rolling.RollingFileAppender">
        <file>${user.dir}/web/logs/access.log</file>
        <rollingPolicy class="ch.qos.logback.core.rolling.TimeBasedRollingPolicy">
            <fileNamePattern>access-log-%d{yyyy-MM-dd}.gz</fileNamePattern>
            <maxHistory>7</maxHistory>
        </rollingPolicy>
        <encoder>
            <pattern>%date{yyyy-MM-dd HH:mm:ss ZZZZ} %message%n</pattern>
            <immediateFlush>false</immediateFlush>
        </encoder>
    </appender>

    <logger name="access" level="INFO" additivity="false">
        <appender-ref ref="ACCESS_FILE"/>
    </logger>

    <logger name="be.objectify.deadbolt.java.actions.AbstractDeadboltAction" level="OFF"/>
    <logger name="application" level="WARN"/>
    <logger name="play" level="WARN"/>

    <root level="ERROR">
        <appender-ref ref="LOGSTASH-ASYNC"/>
        <appender-ref ref="FILE-ASYNC"/>
        <appender-ref ref="SENTRY-ASYNC"/>
    </root>

</configuration>

然后数组的第一个元素将对应于第一行等

Answer 2

试试这个：

    words = somestring.split()
    for i in range(len(words)):
        try:
            locals()['int_%s'%(i)] = int(words[i])
        exept:
            pass

Answer 3

您可以使用for循环和is_digit方法制作。

像这样：

# let's guess input text is called TEXT.
TEXT = '''\
Some first text:  2342
Another line here:  284
Maybe third line: 458
And forth line: 199'''

# we can make like this:
splited_TEXT = TEXT.split('\n')
# make new(wanted) dictionary
new_dict = {}

# then use for loop:
for num, sentence in enumerate(splited_TEXT):
    for word in sentence.split(' '): # split by space
        if word.is_digit: # check if word is digit
            new_dict[num] = word
            continue
print(new_dict)

然后你可以查看{0：2342,1：284 ......}

Answer 4

我发现这条简单的线条有效：

[int(s) for s in TEXT.split() if s.isdigit()]

对于上面的TEXT。

Python按行将字符串转换为整数？

4 个答案: