Question

我有一个有两个部分的表单，一个用于信息，第二个是用户可以查看的长列表。这是代码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<form method="post">
<h1> Basic Info </h1>
<input type="text" name="title" />
<input type="text" name="city" />
<input type="text" name="location" />
<input type="text" name="type" />
<h1> Features </h1>
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
<input name="feature" type="radio" />
</form>
</body>
</html>

我有两个表（p_detail和p_feature），我希望在p_detail表中插入用户基本信息，并在p_feature表中插入要素。我的p_feature表有以下列，（id，property_id，features）和我的p_detail有（id，title，location，city等）。主要问题在于p_feature表，我希望p_detail中的id在property_id中应该是相同的在p_feature中。我怎么能这样做？

问候

Answer 1

假设'id'是p_deatil中的增量主键，

插入'p_detail'后，您将获得insert_id like，

$id_p_detail = $mysqli->insert_id;

如何在mysql

1 个答案: