Question

我正在使用此功能：GetLogicalDriveStringsW(ARRAYSIZE(myDrives) - 1, myDrives) 然后我循环遍历所有检索到的驱动器。

时我需要驱动器号

char driveLetter;
UINT driveType;
WCHAR myDrives[105];

for (LPWSTR drive = myDrives; *drive != 0; drive += 4)
{
    driveType = GetDriveTypeW(drive);
    if (driveType == DRIVE_CDROM)
    {             
        **driveLetter = // (drive) Need just the drive character** 
    }           
}

在使用上述功能时如何获取驱动器字符的任何想法？

Answer 1

驱动器号都是纯ASCII，这意味着它们与char和wchar_t具有完全相同的值。

Answer 2

驱动器号始终位于A..Z范围内，在Windows上，当您处理ASCII范围内的字符时，您可以使用简单的转换从WCHAR转换为char：< / p>

const WCHAR* somepath = L"c:\\foo";
char driveletter;
driveletter = (char) *somepath;
printf("letter: %c\n", driveletter);

这在Windows上是安全的，因为WCHAR编码为UTF-16LE，而char / CHAR编码的代码页是ASCII的超集。您无法对其他平台上的char和wchar_t做出相同的假设。

我个人更喜欢使用GetLogicalDrives而不是GetLogicalDriveStrings：

char driveletter;
WCHAR rootpath[] = L"?:\\";
DWORD validdrives = GetLogicalDrives();
for (UINT i = 0; i < 26; ++i)
{
    if (validdrives & (1 << i))
    {
        driveletter = 'A' + i;
        rootpath[0] = driveletter;
        UINT drivetype = GetDriveTypeW(rootpath);
        printf("Drive %c (%ls) is type %u\n", driveletter, rootpath, drivetype);
        if (drivetype == DRIVE_CDROM)
        {
            printf("CD-Rom drive letter %c\n", driveletter);
        }
    }
}

Answer 3

只需调用GetLogicalDriveStrings()和GetDriveType()的Ansi版本，而不是Unicode版本：

char driveLetter = 0;
CHAR myDrives[105] = {};

GetLogicalDriveStringsA(104, myDrives);
for (LPSTR drive = myDrives; *drive != 0; drive += 4) {
    if (GetDriveTypeA(drive) == DRIVE_CDROM) {
        driveLetter = *drive;
        break;
    }
}

将LPWSTR转换为char

3 个答案: