Selenium webdriver无法在chrome:// downloads

时间:2017-02-26 12:49:03

标签: python google-chrome selenium selenium-webdriver selenium-chromedriver

我在蟒蛇中使用了硒与chromedriver。

我的问题是,当我尝试访问chrome下载页面上的元素时,selenium会给我一个错误(chrome:// downloads)。 例如,我尝试获取文件网址" http://file.jpg"。

<a id="url" target="_blank" href="http://file.jpg">http://file.jpg</a>

但是当我试图通过它的id获取元素时,我得到了一个异常。

代码:

driver = webdriver.Chrome("chromedriver.exe")
driver.get("chrome://downloads/")
file_url = driver.find_element_by_id("url").get_attribute("href")

例外:

Traceback (most recent call last):
  File "<pyshell#34>", line 3, in <module>
    driver.find_element_by_id("url")
  File "D:\Python\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 269, in find_element_by_id
    return self.find_element(by=By.ID, value=id_)
  File "D:\Python\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 752, in find_element
    'value': value})['value']
  File "D:\Python\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 236, in execute
    self.error_handler.check_response(response)
  File "D:\Python\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 192, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"id","selector":"url"}
  (Session info: chrome=56.0.2924.87)
  (Driver info: chromedriver=2.27.440174 (e97a722caafc2d3a8b807ee115bfb307f7d2cfd9),platform=Windows NT 10.0.10586 x86_64)

通过driver.execute_script()使用javascript也不适用于我。 当我在浏览器中看到元素时,为什么我会得到NoSuchElementException

1 个答案:

答案 0 :(得分:5)

目标链接位于多个shadow-root块内。试试这个:

driver = webdriver.Chrome("chromedriver.exe")
driver.get("chrome://downloads/")

manager = driver.find_element_by_css_selector('body/deep/downloads-manager')
item = manager.find_element_by_css_selector('body/deep/downloads-item')
shadow = driver.execute_script('return arguments[0].shadowRoot;', item)
link = shadow.find_element_by_css_selector('div#title-area>a')

file_url = link.get_attribute("href")