Question

我有一个奇怪的问题。我正在尝试创建一个报价生成器，其中包含引用部分的字典（每个值都是一个列表），从该列表中为每个键提取一个随机项，并将其附加到另一个列表。然后将打印该列表以显示最终报价。

但是，我按随机顺序得到引用的部分。在跑步时，我得到这样的东西：

['avoid ', 'hobby.', "it's easy to ", 'your ', 'Occasionally ', 'most important ']

这是我的代码：

from random import choice

quoteWords = {
    "one": ["Sometimes ", "Often ", "Occasionally ", "Usually "],
    "two": ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "],
    "three": ["do ", "avoid ", "finish", "create ", "witness "],
    "four": ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "],
    "five": ["best ", "most important ", "funniest "],
    "six": ["work.", "art.", "hobby.", "posessions."],
}

def inspire():
    quote = []
    counter = 0
    for key in quoteWords:
        quote.insert(counter, choice(quoteWords[key]))
        counter += 1
    return(quote)

print(inspire())

非常感谢任何帮助。提前谢谢！

Answer 1

字典没有订单。

for key in quoteWords没有保证将返回keys的订单。

您应该使用OrderedDict：

from random import choice
from collections import OrderedDict

quoteWords = OrderedDict()

quoteWords['one'] = ["Sometimes ", "Often ", "Occasionally ", "Usually "]
quoteWords['two'] = ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "]
quoteWords['three'] = ["do ", "avoid ", "finish", "create ", "witness "]
quoteWords['four'] = ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "]
quoteWords['five'] = ["best ", "most important ", "funniest "]
quoteWords['six'] = ["work.", "art.", "hobby.", "posessions."]

# or create directly from list of tuples as in @schwobaseggl's answer.

def inspire():
    quote = []
    counter = 0
    for key in quoteWords:

        quote.insert(counter, choice(quoteWords[key]))
        counter += 1
    return(quote)

Answer 2

您可以使用OrderedDict！在常见的dict中，无法保证keys'或items'顺序：

from collections import OrderedDict
quoteWords = OrderedDict([
    ("one", ["Sometimes ", "Often ", "Occasionally ", "Usually "]),
    ("two", ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "]),
    ("three", ["do ", "avoid ", "finish", "create ", "witness "]),
    ("four", ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "]),
    ("five", ["best ", "most important ", "funniest "]),
    ("six", ["work.", "art.", "hobby.", "posessions."]),
])
# ...
print(''.join(inspire()))
Usually you should witness the best work.

您使用它的方式，甚至不需要映射。您可以使用列表列表并从每个列表中选择一个项目。

Answer 3

我猜你使用的是Python2。在Python中，虽然你的代码在Python3中正确运行，但dict没有被订购（感谢@schwobaseggl）：

(ins)>>> quoteWords = {
(ins)...     "one": ["Sometimes ", "Often ", "Occasionally ", "Usually "],
(ins)...     "two": ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "],
(ins)...     "three": ["do ", "avoid ", "finish", "create ", "witness "],
(ins)...     "four": ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "],
(ins)...     "five": ["best ", "most important ", "funniest "],
(ins)...     "six": ["work.", "art.", "hobby.", "posessions."],
(ins)... }
(ins)>>> quoteWords
{'six': ['work.', 'art.', 'hobby.', 'posessions.'], 'three': ['do ', 'avoid ', 'finish', 'create ', 'witness '], 'two': ["it's best to ", 'you should ', "you shouldn't ", "it's easy to ", "it's hard to "], 'four': ['the ', 'a ', 'your ', "society's ", "your friends' ", "the government's "], 'five': ['best ', 'most important ', 'funniest '], 'one': ['Sometimes ', 'Often ', 'Occasionally ', 'Usually ']}

只需使用列表来解决问题。更重要的是，使用append比insert更方便：

from random import choice

quoteWords = [
    ["Sometimes ", "Often ", "Occasionally ", "Usually "],
    ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "],
    ["do ", "avoid ", "finish", "create ", "witness "],
    ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "],
    ["best ", "most important ", "funniest "],
    ["work.", "art.", "hobby.", "posessions."],
]

def inspire():
    quote = []
    for choices in quoteWords:
        quote.append(choice(choices))
    return(quote)

print(inspire())

按顺序追加for循环中的字典列表（Python 3）

3 个答案: