Firebase Auth无法登录

时间:2017-02-26 07:13:43

标签: android firebase firebase-authentication

我尝试将Firebase身份验证集成到我的第一个Firebase应用程序中,但是遇到了一个奇怪的问题。我使用登录和注册功能将Firebase Auth集成到我的登录活动中,但每当我尝试测试应用程序并尝试注册虚拟用户时,没有任何反应,并且没有运行InfoActivity的意图。

我的代码:

import android.content.Intent;
import android.support.annotation.NonNull;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;

import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;
import com.google.firebase.auth.FirebaseUser;

public class LoginActivity extends AppCompatActivity {

    private FirebaseAuth mAuth;

    EditText email;

    EditText password;

    String emailString;

    String passwordString;

    Button login;

    TextView signUp;

    int status = 0;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_login);

        mAuth = FirebaseAuth.getInstance();

        email = (EditText) findViewById(R.id.email);

        password = (EditText) findViewById(R.id.password);

        login = (Button) findViewById(R.id.login);

        signUp = (TextView) findViewById(R.id.signUp);

        login.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                emailString = email.getText().toString().trim();

                passwordString = password.getText().toString().trim();

                if (status == 0) {

                    loginMethod(emailString, passwordString)

                } else if (status == 1) {

                    signUpMethod(emailString, passwordString);

                }

            }
        });

        signUp.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                if (status == 0) {

                    status = 1;

                    login.setText("Sign Up");

                    signUp.setText("Login");

                } else if (status == 1) {

                    status = 0;

                    login.setText("Login");

                    signUp.setText("Sign Up");

                }
            }
        });
    }

    public void loginMethod(String email, String password) {


        mAuth.signInWithEmailAndPassword(email, password)
                .addOnCompleteListener(LoginActivity.this, new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {

                        if (task.isSuccessful()) {

                            Log.i("Task:", "Complete");

                            Intent i = new Intent(LoginActivity.this, InfoActivity.class);

                            startActivity(i);

                        }

                        if (!task.isSuccessful()) {

                            Toast.makeText(LoginActivity.this, "Login Failed",
                                    Toast.LENGTH_SHORT).show();

                        }

                    }
                });

    }

    public void signUpMethod(String email, String password) {

        mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
            @Override
            public void onComplete(@NonNull Task<AuthResult> task) {

                if (task.isSuccessful()) {
                    Intent i = new Intent(LoginActivity.this, InfoActivity.class);

                    startActivity(i);
                }

                if (!task.isSuccessful()) {
                    Toast.makeText(LoginActivity.this, "Sign Up Failed",
                            Toast.LENGTH_SHORT).show();
                }
            }
        });
    }
}

我已经在我的应用的iOS版本中使用Firebase Auth,但令人惊讶的是,它不适用于Android版本。你们中的任何人都可以帮我解决这个问题吗?

0 个答案:

没有答案