使用特定的编码来读取ZipArchive

时间:2017-02-25 22:10:53

标签: c# codepages system.io.compression

请告诉我,如何实现Encoding.GetEncoding(“cp866”)? 在从存档导出过程中,俄罗斯符号未正确显示。

public static class ZipArchiveExtension
{
    public static void ExtractToDirectory(this ZipArchive archive, string destinationDirectoryName, bool overwrite)
    {
        if (!overwrite)
        {
            archive.ExtractToDirectory(destinationDirectoryName);
            return;
        }
        foreach (ZipArchiveEntry file in archive.Entries)
        {
            string completeFileName = Path.Combine(destinationDirectoryName, file.FullName);
            if (file.Name == "")
            {
                Directory.CreateDirectory(Path.GetDirectoryName(completeFileName));
                continue;
            }
            file.ExtractToFile(completeFileName, true);
        }
    }
}

FileStream zipToOpen = new FileStream(zipPath, FileMode.Open);
ZipArchive archive = new ZipArchive(zipToOpen);
ZipArchiveExtension.ExtractToDirectory(archive, extractPath, true);
zipToOpen.Dispose();

与System.IO.Compression中一样:ZipFile.ExtractToDirectory(zipPath,extractPath,Encoding.GetEncoding(“cp866”));

1 个答案:

答案 0 :(得分:1)

为了在ZipArchive上使用特定编码,需要在构造函数中指定。

您应该能够使用4参数构造函数:

ZipArchive archive = new ZipArchive(zipToOpen, ZipArchiveMode.Read, false, Encoding.GetEncoding("cp866"));

https://msdn.microsoft.com/en-us/library/hh875101(v=vs.110).aspx