错误1无法隐式转换类型＆＃39; double＆＃39; to＆＃39; int＆＃39;。存在显式转换（您是否错过了演员？）

Question

我说这个C＃代码有错误＆＃34;错误1无法隐式转换类型＆＃39; double＆＃39; to＆＃39; int＆＃39;。存在显式转换（您是否错过了演员？）＆＃34; 错误在哪里？

        Console.Write("Input money : ");
        float money;
        int tax;
        if (money < 10000)
        {
            tax = .05 * money;
        }
        else if (money <= 100000)
        {
            tax = .08 * money;
        }
        else
        {
            tax = .085 * money;
        }

        Console.WriteLine("Tax is {0}", tax);
        Console.ReadLine();
    }
}

Answer 1

将您的可变税改为双倍

  double tax = 0;

工作守则，

Console.Write("Input money : ");
float money = Console.Read();          
double tax = 0;
if (money < 10000)
{
    tax = .05 * money;
}
else if (money <= 100000)
{
    tax = .08 * money;
}
else
{
    tax = .085 * money;
}

Console.WriteLine("Tax is {0}", tax);
Console.ReadLine();

Answer 2

tax是int，您尝试为其分配float值。

您必须将tax / float / double声明为decimal或以某种方式对其值进行四舍五入。

编辑：如果你不初始化money的值，使用Console.ReadLine()并解析其返回值

，这也很奇怪