我正在尝试使用Chat
将compose
组件包含两个查询和一个变异。
但是,我仍然在控制台中收到以下错误:
未捕获错误:
react-apollo
仅支持每个HOC的查询,订阅或突变。[object Object]
有2个查询,0个订阅和0个突变。您可以使用“compose
”将多种操作类型连接到组件
以下是我的查询和导出声明:
// this query seems to cause the issue
const findConversations = gql`
query allConversations($customerId: ID!) {
allConversations(filter: {
customerId: $customerId
})
} {
id
}
`
const createMessage = gql`
mutation createMessage($text: String!, $conversationId: ID!) {
createMessage(text: $text, conversationId: $conversationId) {
id
text
}
}
`
const allMessages = gql`
query allMessages($conversationId: ID!) {
allMessages(filter: {
conversation: {
id: $conversationId
}
})
{
text
createdAt
}
}
`
export default compose(
graphql(findConversations, {name: 'findConversationsQuery'}),
graphql(allMessages, {name: 'allMessagesQuery'}),
graphql(createMessage, {name : 'createMessageMutation'})
)(Chat)
显然,问题在于findConversations
查询。如果我将其注释掉,我就不会收到错误并且组件正确加载:
// this works
export default compose(
// graphql(findConversations, {name: 'findConversationsQuery'}),
graphql(allMessages, {name: 'allMessagesQuery'}),
graphql(createMessage, {name : 'createMessageMutation'})
)(Chat)
谁能告诉我我缺少什么?
顺便说一句,我也在allMessagesQuery
设置订阅,如果相关的话:
componentDidMount() {
this.newMessageSubscription = this.props.allMessagesQuery.subscribeToMore({
document: gql`
subscription {
createMessage(filter: {
conversation: {
id: "${this.props.conversationId}"
}
}) {
text
createdAt
}
}
`,
updateQuery: (previousState, {subscriptionData}) => {
...
},
onError: (err) => console.error(err),
})
}
答案 0 :(得分:5)
您的findConversationsQuery
实际上是两个查询。这一个:
query allConversations($customerId: ID!) {
allConversations(filter: {
customerId: $customerId
})
}
这一个:
{
id
}
整个查询需要包含在一对开始和结束括号中。
我认为你的意思是:
query allConversations($customerId: ID!) {
allConversations(filter: { customerId: $customerId }){
id
}
}