我编写了一个程序来对角打印给定的字符串(如x)
输入:PROGRAM
预期产出:
P M
R A
O R
G
O R
R A
P M
我的输出:
P
M
R
A
O
R
G
R
O
A
R
M
P
我的Java课程:
import java.util.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner in = new Scanner(System.in);
String s = in.nextLine();
char[] word = new char[100];
word = s.toCharArray();
int count=0;
int k = s.length()-1;
for (int i=0;i<s.length();i++){
for (int j=0;j<s.length();j++){
if(!(i==k))
System.out.println(word[i]);
for(int x=0;x<s.length()-count;x++)
System.out.print(" ");
System.out.println(word[k]);
k--;
count++;
break;
}
for(int j=0;j<count;j++)
System.out.print(" ");
}
}
}
答案 0 :(得分:0)
您的逻辑仅适用于水平线的上半部分。 完成以下计划:
import java.util.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner in = new Scanner(System.in);
String s = in.nextLine();
char[] word = new char[100];
word = s.toCharArray();
int k = s.length()-1;
int x ;
for (int i=0;i<s.length();i++){
if((i<k))
{
for (x=0; x<i; x++)
System.out.print(" ");
System.out.print(word[i]);
for ( x=0; x<k-i-1; x++)
System.out.print(" ");
System.out.println(word[k]);
k--;
}
else if(i == k){
for ( x=0; x<i; x++)
System.out.print(" ");
System.out.println(word[k]);
k--;
}
else{
for(x = k; x >= 0 ; x--)
System.out.print(" ");
System.out.print(word[k]);
for (x=0; x<i-k-1; x++)
System.out.print(" ");
System.out.println(word[i]);
k--;
}
}
}
}
按照你的说法提供输出。
答案 1 :(得分:0)
BlackArrow提出了一种更简单的打印图案的方法,我们可以将图案存储在二维数组中,然后优雅地打印。代码如下:-
public static void printDiagonalPattern(String str) {
int len = str.length();
//if length is even, then pattern is not possible.
if (len % 2 == 0) {
return;
} else {
char[][] matrix = new char[len][len];
char[] givenString = str.toCharArray();
//prepare elements for first diagonal i.e. up to down.
for (int i = 0, j=0; i<len && j< len; i++, j++) {
matrix[i][j] = givenString[i];
}
//prepare elements for second diagonal i.e. down to up.
for (int i = len-1, j=0; i>=0 && j< len; i--, j++) {
matrix[i][j] = givenString[j];
}
for(int i = 0; i<len; i++) {
for (int j = 0; j<len; j++) {
System.out.print(matrix[i][j]);
}
System.out.println("");
}
}
}
答案 2 :(得分:0)
浏览以下程序,
import java.util.Scanner;
public class PrintWelcome {
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
System.out.println("enter odd string only :");
String s=sc.nextLine();
char c[]=s.toCharArray();
int len=c.length;
if((len&1)==0)
System.out.println("string is prime: ");
else{
System.out.println("String is : "+s.trim()+", length : "+len);
System.out.println("String center letter is : "+c[len/2]);
int i, j=0,k,n=c.length/2,m=n+1;
int last=c.length-1;
int l=c.length-1;
//upper portion
for(i=0; i<=c.length/2; i++)
{
//if(n>=0)
//upper center spaces
for(j=c.length/2;j>i; j--)
{
System.out.print(" ");//upper center spaces
}//upper left array values
for(k=i;k<=i;k++)
{
System.out.print(c[n]);//upper left array values
n--;
}
//}
//upper right part spaces
if(m<=c.length-1)
{
for(j=1; j<i*2; j++)
{
System.out.print(" ");//up
}//upper right values
for(k=m;k<=i+(c.length/2);k++)
{
System.out.print(c[m]);
m++;
}
}
System.out.println();
}
//below pattern
for (int x = 0; x <=c.length/2; x++) {
//below right spaces
for(int y=1;y<=x;y++)
{
System.out.print(" ");
}
//below left values
for(int z=x;z<=x;z++)
{
System.out.print(c[z]);
}
//below center space
for(int p=j-2;p>=x*2;p--)
{
System.out.print(" ");
}
//below right values
if(last>c.length/2)
{
for(int r=last;r<=l;r++)
{
System.out.print(c[r]);
l--;
last--;
}
}
System.out.println();
}
}
}
}