下面是一个简单的查询和结果：是一种将总EVENT聚合7天的方法，然后总计EVENT总数？汇总功能是否有效？我正在使用SQL SERVER 05＆amp; 08.再次感谢，伙计们。
SELECT DATE_SOLD, count(DISTINCT PRODUCTS) AS PRODUCT_SOLD
FROM PRODUCTS
WHERE DATE >='10/1/2009'
and DATE <'10/1/2010'
GROUP BY DATE_SOLD
结果：
DATE_SOLD PRODUCT_SOLD
10/1/09 5
10/2/09 11
10/3/09 14
10/4/09 6
10/5/09 11
10/6/09 13
10/7/09 10
Total 70
10/8/09 4
10/9/09 11
10/10/09 8
10/11/09 4
10/12/09 7
10/13/09 4
10/14/09 9
Total 47
答案 0 :(得分：0)
没有你的桌面设计可以使用这里我认为你想要的（虽然我必须承认输出需要清理）。它至少应该让你找到你正在寻找的解决方案。
CREATE TABLE MyTable(
event_date date,
event_type char(1)
)
GO
INSERT MyTable VALUES ('2009-1-01', 'A')
INSERT MyTable VALUES ('2009-1-11', 'B')
INSERT MyTable VALUES ('2009-1-11', 'C')
INSERT MyTable VALUES ('2009-1-20', 'N')
INSERT MyTable VALUES ('2009-1-20', 'N')
INSERT MyTable VALUES ('2009-5-23', 'D')
INSERT MyTable VALUES ('2009-5-23', 'E')
INSERT MyTable VALUES ('2009-5-10', 'F')
INSERT MyTable VALUES ('2009-5-10', 'F')
GO
WITH T AS (
SELECT DATEPART(MONTH, event_date) event_month, event_date, event_type
FROM MyTable
)
SELECT CASE WHEN (GROUPING(event_month) = 0)
THEN event_month ELSE '99' END AS event_month,
CASE WHEN (GROUPING(event_date) = 1)
THEN '9999-12-31' ELSE event_date END AS event_date,
COUNT(DISTINCT event_type) AS event_count
FROM T
GROUP BY event_month, event_date WITH ROLLUP
ORDER BY event_month, event_date
这给出了以下输出：
event_month event_date event_count
1 2009-01-01 1
1 2009-01-11 2
1 2009-01-20 1
1 9999-12-31 4
5 2009-05-10 1
5 2009-05-23 2
5 9999-12-31 3
99 9999-12-31 7
月份为“99”，年份为“9999-12-31”为总数。
答案 1 :(得分：0)
SELECT DATEDIFF(week, 0, DATE_SOLD) Week,
DATEADD(week, DATEDIFF(week, 0, DATE_SOLD), 0) From,
DATEADD(week, DATEDIFF(week, 0, DATE_SOLD), 0) + 6 To,
COUNT(DISTINCT PRODUCTS) PRODUCT_SOLD
FROM dbo.PRODUCTS
WHERE DATE >= '2009-10-01'
AND DATE < '2010-10-01'
GROUP BY DATEDIFF(week, 0, DATE_SOLD) WITH ROLLUP
ORDER BY DATEDIFF(week, 0, DATE_SOLD)