Question

这是视图中的ajax函数

 <script type="text/javascript">

        $('#name').on('change',function(){
            var uid = document.getElementById('name').value;

            $.ajax({
                    url : '<?php echo base_url('index.php/Manager_Settings_Controller/getUsername');?>',
                    method : 'get',
                    data : {'uid' : uid },

                    success : function(result){

                            console.log(result);


                            }
        });

        });

这是控制器的getUsername函数

 public function getUsername(){
    $uid = $this->input->get('uid');
    $this->load->model('Manager_Settings_Model');
    $data = $this->Manager_Settings_Model->getUsername($uid);
    return $data['username'];


}

这是模型功能

    function getUsername($uid){
         $this->db->select('username');
         $query = $this->db->get_where('user',array('u_id'=>$uid));
         foreach($query -> result() as $row){
             $data = array(
                'username' => $row->username,


                );
            }
        return $data;

}

如果有人可以帮助我真的很棒。谢谢inadvance

Answer 1

  public function getUsername(){
        $uid = $this->input->get('uid');
        $this->load->model('Manager_Settings_Model');
        $data = $this->Manager_Settings_Model->getUsername($uid);
        echo $data['username'];      
    }

你必须在控制器中回显不返回，所以你在ajax的成功函数的console.log中得到错误或结果。

我无法从CI中的视图中获取控制器返回的值到ajax成功函数

1 个答案: