Question

我有以下代码。我从其他页面通过get方法获得时间到feedback.php。

现在我需要将此值从feedback.php传递到此行的chart.js ['你所用的时间是'，时间] 然后它将在feedback.php页面上显示图表。我怎样才能完成这件事？

feedback.php

 <script src="chart.js"></script>
 <div id="chart_div"></div>
 <div id="chart_div"></div>

  **<?php $time= $_GET["sec"];?><br>**

chart.js之

  var data = google.visualization.arrayToDataTable([
    ['Time', 'Time taken by worker'],
    ['Worker 1 ', 200],
    ['Worker 2', 150],
    ['Worker 3', 300],
    ['Worker 4', 160],
    ['Worker 5', 140],
    ['Time taken by you is', time]
  ]);

Answer 1

尝试下面

在加载chart.js

之前定义时间变量

<script>
    var TIME_VAR = '<?=$_GET["sec"];?>';
 </script>

然后加载 <script src="chart.js"></script>

在 chart.js 中，您可以使用 TIME_VAR

var data = google.visualization.arrayToDataTable([
    ['Time', 'Time taken by worker'],
    ['Worker 1 ', 200],
    ['Worker 2', 150],
    ['Worker 3', 300],
    ['Worker 4', 160],
    ['Worker 5', 140],
    ['Time taken by you is',TIME_VAR]
  ]);

将值从php传递给Jscript

1 个答案: