我试图在php表格中显示json内容,但我每次都会收到错误。我有一些语法错误,无法弄清楚我应该改变什么?
PS。尝试用Slim框架构建它
这是我的代码:
<div class="data-table-wrapper">
<?php
$myData = file_get_contents("http://ergast.com/api/f1/current.json");
$myObject = json_decode($myData);
?>
<table class="data-table">
<thead>
<tr>
<td>Date</td>
<td>Time</td>
<td>Round</td>
<td>Circuit</td>
<td>Location</td>
</tr>
</thead>
<?PHP
foreach($myObject as $key=>$item);
?>
<tr>
<td><?PHP echo $item->Date; ?></td>
<td><?PHP echo $item->Time; ?></td>
<td><?PHP echo $item->Round; ?></td>
<td><?PHP echo $item->Circuit; ?></td>
<td><?PHP echo $item->Location; ?></td>
</tr>
<?PHP
}
?>
</table>
</div>
我的错误是:
注意:第38行的C:\ xampp \ htdocs \ challenge \ app \ view \ challenge.php中的未定义属性:stdClass :: $ Date
注意:第39行的C:\ xampp \ htdocs \ challenge \ app \ view \ challenge.php中的未定义属性:stdClass :: $ Time
注意:未定义的属性:第40行的C:\ xampp \ htdocs \ challenge \ app \ view \ challenge.php中的stdClass :: $ Round
注意:第41行的C:\ xampp \ htdocs \ challenge \ app \ view \ challenge.php中的未定义属性:stdClass :: $ Circuit
答案 0 :(得分:4)
与代码相比,我刚刚查看了您的json
格式。映射到json
的路径不正确。我已经纠正了以下内容;
请查看以下内容:
PHP代码:
$myData = file_get_contents("http://ergast.com/api/f1/current.json");
$myObject = json_decode($myData);
$myObjectMap = $myObject->MRData->RaceTable->Races;
对于每种格式:
<?php foreach($myObjectMap as $key => $item): ?>
<tr>
<td><?PHP echo $item->date; ?></td>
<td><?PHP echo $item->time; ?></td>
<td><?PHP echo $item->round; ?></td>
<td><?PHP echo $item->Circuit->circuitId; ?></td>
<td><?PHP echo $item->Circuit->Location->country; ?></td>
</tr>
<?php endforeach; ?>
完整代码:
<html>
<head>
<title>PHP</title>
</head>
<body>
<?php
$myData = file_get_contents("http://ergast.com/api/f1/current.json");
$myObject = json_decode($myData);
$myObjectMap = $myObject->MRData->RaceTable->Races;
?>
<table>
<thead>
<tr>
<td>Date</td>
<td>Time</td>
<td>Round</td>
<td>Circuit</td>
<td>Location</td>
</tr>
</thead>
<tbody>
<?php foreach($myObjectMap as $key => $item): ?>
<tr>
<td><?PHP echo $item->date; ?></td>
<td><?PHP echo $item->time; ?></td>
<td><?PHP echo $item->round; ?></td>
<td><?PHP echo $item->Circuit->circuitId; ?></td>
<td><?PHP echo $item->Circuit->Location->country; ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
</body>
</html>
答案 1 :(得分:0)
问题是解码数组的外观不同。在循环之前转储编码数组以了解正确的数据结构或使用JSON beautify service。还可以使用右上/小写来寻址属性。更新的循环可能如下所示:
<div class="data-table-wrapper">
<?php
$myData = file_get_contents("http://ergast.com/api/f1/current.json");
$myObject = json_decode($myData);
?>
<table class="data-table">
<thead>
<tr>
<td>Date</td>
<td>Time</td>
<td>Round</td>
<td>Circuit</td>
<td>Location</td>
</tr>
<?PHP
foreach($myObject->MRData->RaceTable->Races as $key=>$item){
?>
<tr>
<td><?PHP echo $item->date; ?></td>
<td><?PHP echo $item->time; ?></td>
<td><?PHP echo $item->round; ?></td>
<td><?PHP echo $item->Circuit->circuitName; ?></td>
<td><?PHP echo $item->Circuit->Location->locality; ?></td>
</tr>
<?PHP
}
?>
</table>
</div>
</div>