Question

我的模型如下

class Quote < ActiveRecord::Base

  named_scope :from_affiliate_id, Proc.new { |id|
    { :select => "COUNT(*) as count_all, date(created_at) as date_created_at",
      :conditions => {:affiliate_id => id},
      :group => "date(created_at)",

    }
  }
  named_scope :in_dates, Proc.new {|from,to|{ :conditions => ["date(created_at) >= ? and date(created_at) <= ?",from,to]}}

  belongs_to :affiliate

  def self.create_quote(value = '')
    return if value.nil?
    quote = self.new(:affiliate_id => value)
    quote.save
  end

end

当我做Quote.from_affiliate_id（1）时，我得到以下结果

[#<Quote >, #<Quote >, #<Quote >, #<Quote >]

我希望得到一个有序的哈希。哪个应该有一个日期作为键并计为值。请帮帮我。感谢期待

Answer 1

Quote.from_affiliate_id(1).inject({}) do |h,q|
  h[q.created_at] = q.count_all
  h
end

Answer 2

尝试

ActiveSupport::OrderedHash[*Quote.from_affiliate_id(1).map {|q|
  [q.created_at, q.count_all]
}.flatten]

不会订购创建普通哈希：

>> ActiveSupport::OrderedHash[4,3,2,1].to_a
=> [[4, 3], [2, 1]]

VS

>> Hash[4,3,2,1].to_a
=> [[2, 1], [4, 3]]

获得有序哈希

2 个答案: