我正在研究“学习python the hardway”。如果这是重复的话,我道歉但我真的无法弄清楚我做错了什么。当我输入少于50的东西时,它告诉我再试一次,第二次在另一个函数中调用一个字符串。如果我在第二个条目上输入大于50的相同内容,则在另一个函数中调用另一个字符串。它会从green_dragon()调用并打印出来“两条龙都会让你活着并吃掉你。”感谢您提供的任何见解。我为简单而道歉,哈哈。不得不制作我自己的“游戏,我还没那么有创意,哈哈。”
def gold_room():
print "You have entered a large room filled with gold."
print "How many pieces of this gold are you going to try and take?"
choice = raw_input("> ")
how_much = int(choice)
too_much = False
while True:
if how_much <= 50 and too_much:
print "Nice! you're not too greedy!"
print "Enjoy the gold you lucky S.O.B!"
exit("Bye!")
elif how_much > 50 and not too_much:
print "You greedy MFKR!"
print "Angered by your greed,"
print "the dragons roar and scare you into taking less."
else:
print "Try again!"
return how_much
def green_dragon():
print "You approach the green dragon."
print "It looks at you warily."
print "What do you do?"
wrong_ans = False
while True:
choice = raw_input("> ")
if choice == "yell at dragon" and wrong_ans:
dead("The Green Dragon incinerates you with it's fire breath!")
elif choice == "approach slowly" and not wrong_ans:
print "It shows you its chained collar."
elif choice == "remove collar"and not wrong_ans:
print "The dragon thanks you by showing you into a new room."
gold_room()
else:
print "Both dragons cook you alive and eat you."
exit()
答案 0 :(得分:1)
too_much = False
if <= 50 and too_much
如果too_much
设置为False,为什么期望if表达式计算为true?它永远不会进入if
。
也可以在循环内移动用户输入。
编辑:
停止你的while循环:
too_much = True
while too_much:
choice = raw_input("> ")
how_much = int(choice)
if how_much <= 50:
print "Nice! you're not too greedy!"
print "Enjoy the gold you lucky S.O.B!"
too_much = False
else:
print "You greedy MFKR!"
print "Angered by your greed,"
print "the dragons roar and scare you into taking less."