Question

所以我使用带有JPA和Spring MVC的Spring Data用Spring Boot编写这个Web应用程序，我想进行模拟控制器测试。我想出了如何测试get方法，但在我的控制器post方法中，新的JPA实体要么是持久化的，要么是用我的服务更新的。这是我的控制器的样子：

@Controller
@RequestMapping("/registerMember")
public class RegisterMemberController {

    @Autowired
    private MemberService memberService;

    @GetMapping
    public String index(RegisterMemberBean registerMemberBean) {
        return "registerMember";
    }

    @PostMapping
    public String handleSubmit(@Valid RegisterMemberBean registerMemberBean, BindingResult bindingResult, Model model) {
        Member member = registerMemberBean.getMember();
        boolean isRepeatPasswordCorrect = !isRepeatPasswordIncorrect(member.getPassword(), registerMemberBean.getComparePassword());

        if(isAnyErrors(isRepeatPasswordCorrect, !bindingResult.hasErrors())) {
            if(!isRepeatPasswordCorrect) {
                model.addAttribute("isRepeatPasswordIncorrect", true).
                addAttribute("isRepeatPasswordIncorrectMsg", "Passwords don't match");
            }
            return "registerMember";
        }

        boolean errUsername = !memberService.isNoOtherEntityWithUserName(0, member.getUserName());
        boolean errEmail = !memberService.isNoOtherEntityWithEmail(0, member.getEmail());

        if(errUsername || errEmail) {
            if(errUsername) {
                model.addAttribute("isExistingUserName", true).addAttribute("isExistingUserNameMsg", "Already a user with that username");
            } if(errEmail) {
                model.addAttribute("isExistingEmail", true).addAttribute("isExistingEmailMsg", "Already a user with that email");
            }
            return "registerMember";
        }

        getMainService().save(member);
        return redirectTo("index", new RedirectEntity("member", member.getId()));
    }


}

现在在我的模拟控制器测试中，我想确保我的post方法执行以下操作：

如果BindingResults有任何错误，请重新加载页面
我的服务在db中保留成员JPA实体（如果没有错误）
方法将我重定向到索引页

这是我（差）测试类到目前为止的样子：

@RunWith(SpringRunner.class)
@TestPropertySource(locations="classpath:application_test.properties")
@WebAppConfiguration
public class RegisterMemberControllerTest {

    private MockMvc mockMvc;

    @MockBean
    private MemberService memberService;

    @MockBean
    private RegisterMemberController controller;

    @Before
    public void init() {
        mockMvc = MockMvcBuilders.standaloneSetup(controller).setViewResolvers(new StandaloneMvcTestViewResolver()).build();
        controller.setMainService(memberService);
    }

    @Test
    public void testIndex() throws Exception {
        mockMvc.perform(get("/registerMember"))
         .andExpect(status().isOk())
         .andExpect(forwardedUrl("registerMember");
    }

    @Test
    public void testHandleSubmit() throws Exception {
        RegisterMemberBean registerMemberBean = new RegisterMemberBean();
        registerMemberBean.setMember(TestFixture.getValidMemberWithoutReferences());

        Member member = TestFixture.getValidMember();

        mockMvc.perform(post(Page.REGISTER_MEMBER)).andExpect(status().isOk());
        when(mockMvc.perform(post(Page.REGISTER_MEMBER)).andExpect((ResultMatcher) memberService.save(member)).andExpect(forwardedUrl("redirect:/index/member=" + member.getId() + ".html")));

    }
}

Answer 1

我认为应该和不应该嘲笑的内容有点混乱。

如果我正确地阅读了您的问题，您实际上是在尝试对[XmlRoot(ElementName = "Step")] public class WorkflowStep { [XmlAnyElement("Action")] public XmlElement[] Actions { get; set; } }进行单元测试。因此，您很可能不应该模拟该类，但实际上是测试该类。

我相信您会创建RegisterMemberController的{{3}} / fakes / dummies / stubs / mocks，{{1} }和MemberService类。

这些类将由您的单元测试创建并在测试期间交给您的控制器，这将强制测试您有兴趣证明/反驳的逻辑。

仅供参考，在验证调用RegisterMemberBean类时，您将使用模拟。其余类可以是假人或存根。

备注：我建议从handleSubmit（）方法中删除Model参数，因为它似乎没有在任何地方使用。

spring mvc如何测试我的服务在post请求中持久化实体

1 个答案: