Question

我正在尝试从存储用户信息的SQL Server表中执行SELECT *，然后将这些条目与Active Directory数据库进行比较。

如果我指定一个特定的人，它会起作用，但当我尝试将搜索结果整理到数据表中时，它会出错。 Code和Description是同一个。

在数据库中，代码是AD的描述字段中的代码。那么应该发生的是，它将数据库中的所有数据提取到DataTable，对于DataTable我搜索AD中的每个结果，并在AD的电子邮件字段中返回电子邮件地址。同样，当我输入特定的名字和姓氏时它会起作用，但是当我使用下面的代码时，我只是得到一个未处理的异常错误。

这是代码。谢谢！

private void btnRun_Click(object sender, EventArgs e)
{
        DataTable dt = new DataTable();

        string APIdbUser = "dbuser";
        string APIdbServer = "dbserver";
        string APIdbUserPW = "dbpassword";
        string APIdbDatabase = "thedatabase";
        string TrustedConnection = "no";
        var ConnectionTimeout = "30";

        using (SqlConnection myConnection = new SqlConnection("user id=" + APIdbUser + ";" +
                                   "password=" + APIdbUserPW + ";server=" + APIdbServer + ";" +
                                   "Trusted_Connection=" + TrustedConnection + ";" +
                                   "database=" + APIdbDatabase + "; " +
                                   "connection timeout=" + ConnectionTimeout))
        {
            using (var myCommand = new SqlCommand("SELECT * FROM dbo.Users WHERE FirstName!='NULL' AND LastName!='NULL' AND Gender!='NULL';", myConnection))
            {
                myConnection.Open();
                using (SqlDataReader dr = myCommand.ExecuteReader())
                {
                    dt.Load(dr);
                }
                myConnection.Close();
            }
        }

        foreach (DataRow dr in dt.Rows)
        {
            string ldapAddress = "LDAP://url";
            string ldapusername = "ldapuser";
            string ldappassword = "ldapuser";

            DirectoryEntry de = new DirectoryEntry(ldapAddress, ldapusername, ldappassword);
            DirectorySearcher ds = new DirectorySearcher(de);

            ds.Filter = "(&((&(objectCategory=person)(objectClass=user)))(givenName=" + dr.Field<string>("FirstName") + ")(sn=" + dr.Field<string>("LastName") + ")(description=" + dr.Field<string>("Code") + "))";
            ds.SearchScope = SearchScope.Subtree;

            SearchResult rs = ds.FindOne();

            if (dr.Field<string>("Code") == rs.GetDirectoryEntry().Properties["description"].Value.ToString())
            {
                MessageBox.Show("This users email address is: " + rs.GetDirectoryEntry().Properties["mail"].Value.ToString());
            }
            //MessageBox.Show(dr.Field<string>("FirstName") + " " + dr.Field<string>("LastName"));
        }
}

以下是我修复它的方法

if (rs != null)
{
    if (dr.Field<string>("Code") == rs.GetDirectoryEntry().Properties["description"].Value.ToString())
    {
        if (rs.GetDirectoryEntry().Properties["mail"].Value == null)
        {
            MessageBox.Show("This email is N/A.");
        }
        else
        {
            MessageBox.Show("This users email address is: " + rs.GetDirectoryEntry().Properties["mail"].Value.ToString());
        }
    }
}

Answer 1

必须检查IF NOT null

 if (rs != null)
            {
                if (dr.Field<string>("Code") == rs.GetDirectoryEntry().Properties["description"].Value.ToString())
                {
                    if (rs.GetDirectoryEntry().Properties["mail"].Value == null)
                    {
                        MessageBox.Show("This email is N/A.");
                    }
                    else
                    {
                        MessageBox.Show("This users email address is: " + rs.GetDirectoryEntry().Properties["mail"].Value.ToString());
                    }
                }
            }

搜索由SQL查询构建的DataTable

1 个答案: