Question

我在循环数据和保存到数据库时遇到问题。此插入数据的结果只包含一个。 insert（）与insert_batch（）有什么区别？对不起，我的键盘上的CTRL + K不起作用。

我的观点：

<?php echo form_open('proses_tambah_produk')?>
<input type="file" id="gambar2" name="gambar_tambah[]" class="form-control" style="width:90%;display:initial;margin-right:10px;margin-bottom:5px;">
<label style="background-color:red;color:white;border-radius:50%;padding:3px;" id="idGambar2" class="hapus_gambar glyphicon glyphicon-remove"></label>
<input type="file" id="gambar2" name="gambar_tambah[]" class="form-control" style="width:90%;display:initial;margin-right:10px;margin-bottom:5px;">
<label style="background-color:red;color:white;border-radius:50%;padding:3px;" id="idGambar2" class="hapus_gambar glyphicon glyphicon-remove"></label>
<?php echo form_close()?>

我的控制员：

function proses_tambah_produk(){
        $config['upload_path']          = 'assets/img/produk';
        $config['allowed_types']        = 'gif|jpg|png|jpeg';
        $config['max_size']             = 1000;
        $config['overwrite']             = TRUE;
        //$config['max_width']            = 1024;
        //$config['max_height']           = 768;
        $this->load->library('upload', $config);

        $files = $_FILES;
        $count = count($_FILES['gambar_tambah']['name']);
        for($i=0; $i<$count; $i++)
                {
                $_FILES['gambar_tambah']['name']= $files['gambar_tambah']['name'][$i];
                $_FILES['gambar_tambah']['type']= $files['gambar_tambah']['type'][$i];
                $_FILES['gambar_tambah']['tmp_name']= $files['gambar_tambah']['tmp_name'][$i];
                $_FILES['gambar_tambah']['error']= $files['gambar_tambah']['error'][$i];
                $_FILES['gambar_tambah']['size']= $files['gambar_tambah']['size'][$i];
                $this->upload->do_upload('gambar_tambah');
                $upload_data = $this->upload->data();
                $name_array[] = $upload_data['file_name'];
                $fileName = $upload_data['file_name'];
                $images[] = $fileName;

                }
              $fileName = $images;

            $tambahan = $_FILES['gambar_tambah']['name'];

            $this->produk_adm->add($data, $gambar, $tambahan);

    }

我的模特：

function add($tambahan){
        $last_insert_id = $this->db->insert_id();

        $data_gambar = array(
            'id_produk' => $last_insert_id,
            'gambar'    => $tambahan,
        );
        $this->db->insert('produk_image', $data_gambar);
        return $this->db->insert_id();
    }

Answer 1

$filesCount = count($_FILES['photo_gallery']['name']);    
for($i = 0; $i < $filesCount; $i++){
                    $_FILES['gambar_tambah']['name'] = $_FILES['photo_gallery']['name'][$i];
                    $_FILES['gambar_tambah']['type'] = $_FILES['photo_gallery']['type'][$i];
                    $_FILES['gambar_tambah']['tmp_name'] = $_FILES['photo_gallery']['tmp_name'][$i];
                    $_FILES['gambar_tambah']['error'] = $_FILES['photo_gallery']['error'][$i];
                    $_FILES['gambar_tambah']['size'] = $_FILES['photo_gallery']['size'][$i];
                    $file_name=$this->crud->upload_file('gambar_tambah',$upload_image_path);
                    $image_data[$i]['image'] = $file_name;
                    $this->crud->add('table_name',$image_data[$i]);
                }

Answer 2

你不能两次使用相同的id名称。每个字段的id值必须是唯一的。您上传的代码错误，您正在分配值 $_FILES['gambar_tambah']['name']= $files['gambar_tambah']['name'][$i]; 你不能这样做，你只需要为变量赋值 $image_name = $_FILES['gambar_tambah']['name']; 并在每次循环运行时将其插入到数据库中，或者通过implode函数将其插入到一个字段中。

Answer 3

当您调用模型时，您使用了三个参数，而在模型中则使用了一个参数。

使用

 $this->load->model('produk/adm');
 $this->produk_adm->add($tambahan);

而不是

$this->produk_adm->add($data, $gambar, $tambahan);

和模型

 function add($tambahan){
    $last_insert_id = $this->db->insert_id();

    $data_gambar = array(
        'id_produk' => $last_insert_id, // if it is auto increment in db, remove this line
        'gambar'    => $tambahan,
    );
    $this->db->insert('produk_image', $data_gambar);
    return $this->db->insert_id();
}

使用codeigniter将多个图像数据插入数据库

3 个答案: