Question

如果我输入5，它将生成5（5x5）的方阵我如何乘以1,7,13,19,25？

我的代码是否有适用的算法，所以我可以将对角线相乘或者我需要重写一个新算法？

public partial class Form1 : Form {
    public int e = 0;
    int Row = 0;
    int Column = 0;
    int YAxisPosition = 0; 
    int XAxisPosition = 0;
    int Counter = 0;
    int PositionalValue = 0; 
    TextBox[] MyTextBoxDimA = new TextBox[999999]; 
    TextBox tbRow = new TextBox();
    Button MyButton = new Button();

    public Form1() {
        InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e) {
        AutoScroll = true;
        WindowState = System.Windows.Forms.FormWindowState.Maximized;

        //GENERATING THE SIZE BUTTON
        tbRow = new TextBox();
        tbRow.Text = "5";
        tbRow.Size = new Size(100, 10);
        tbRow.Location = new Point(0, 0);
        Controls.Add(tbRow);

        //GENERATE MATRIX BUTTON
        MyButton = new Button();
        MyButton.Text = "GENERATE MATRIX";
        MyButton.Size = new Size(200, 25);
        MyButton.Click += new EventHandler(MyButton_Click);
        MyButton.Location = new Point(0, 30);
        Controls.Add(MyButton);
    }

    public void MyButton_Click(object sender, EventArgs ee) {
        //CODE FOR GENERATING MATRIX A
        e = 1;
        PositionalValue = 1;
        Counter = 1;

        //POSITION
        YAxisPosition = 60;
        XAxisPosition = 0;
        Row = Convert.ToInt32(tbRow.Text);
        Column = Convert.ToInt32(tbRow.Text);
        while (Row >= e) {
            while (Column >= Counter) {
                MyTextBoxDimA[PositionalValue] = new TextBox(); 
                MyTextBoxDimA[PositionalValue].Location =
                    new Point(XAxisPosition, YAxisPosition); //coordinates (start)
                MyTextBoxDimA[PositionalValue].Size = new Size(70, 10); 
                MyTextBoxDimA[PositionalValue].Text = Convert.ToString(PositionalValue);
                Controls.Add(MyTextBoxDimA[PositionalValue]);
                XAxisPosition = XAxisPosition + 100;
                PositionalValue++;
                Counter++;
            }
            YAxisPosition = YAxisPosition + 50;
            Counter = 1; 
            e++;
            XAxisPosition = 0;
        }
    }
}

Answer 1

如果您正在寻找算法：

    static void Main(string[] args)
    {
        int n = 5;
        int ans = 1;
        int current = 1;
        for (int i = 1; i <= n; i++)
        {
            ans = ans * current;
            current += n + 1;
        }
        Console.WriteLine(ans);
    }

Answer 2

从零循环到矩阵的大小。索引将用于获取每个对角线值（此代码假定每个文本框包含一个整数且不为空白）：

int matrixSize = 5;
int product = 1;
for (int i = 0; i < matrixSize; i++)
{
    product *= int.Parse(MyTextBoxDimA[i,i].Text);
}

如何访问这些数组，以便我可以在对角线中乘以输入的值？

2 个答案: