Question

我需要从用户那里获取每个人的姓名和成绩的输入，将具有相应成绩的人名保存到数组中，以便稍后可以按姓名或成绩进行搜索。这是我到目前为止所得到的

import javax.swing.*;
import java.awt.event.*;
import java.awt.*;
import java.util.*;

public class Grades extends JFrame
    {
    String names;
    int results, count;
    int a;
    //declare Buttons
    private JTextField t1, name, grades;
    private JLabel lbl1, namelbl, gradelbl;

    //constructor
    public Grades()
        {
        super("Grades");

        Container c = getContentPane();
        c.setLayout(new FlowLayout());

        lbl1 = new JLabel("Please enter a number of results");
        c. add(lbl1);

        t1 = new JTextField (2);
        c. add(t1);

        namelbl = new JLabel("Please enter student's name");
        c. add(namelbl);

        name = new JTextField (10);
        c. add(name);

        gradelbl = new JLabel("Please enter student's grade");
        c. add(gradelbl);

        grades = new JTextField (10);
        c. add(grades);


        //create an instance of inner class ButtonHandler
        //to use for button event handling
        ButtonHandler handler = new ButtonHandler();

        t1.addActionListener(handler);
        name.addActionListener(handler);
        grades.addActionListener(handler);

        setSize(400, 400);
        setVisible(true);
        }
    public static void main (String args [])
        {
        Grades app = new Grades();
        app.addWindowListener(
        new WindowAdapter()
            {
            public void windowClosing(WindowEvent e)
                {
                System.exit(0);
                }
            });
        }

    //inner class for button event handling
    private class ButtonHandler implements ActionListener
        {
        public void actionPerformed (ActionEvent e)
            {
            Container c = getContentPane();
                if(e.getSource() == t1)
                    {
                    a = Integer.parseInt(t1.getText());
                    if (a < 2 || a > 25)
                        {
                        JOptionPane.showMessageDialog(null, "You entered wrong value. Please re- enter");
                        t1.requestFocusInWindow();
                        t1.setText("");
                        a = Integer.parseInt(t1.getText());
                        }
                    name.requestFocusInWindow();
                    }
                if(e.getSource() == name)
                    {
                    names = name.getText();
                    grades.requestFocusInWindow();
                    grades.setText("");
                    }
                if(e.getSource() == grades)
                    {
                    results = Integer.parseInt(grades.getText());
                    if(results < 0 || results > 100)
                        {
                        JOptionPane.showMessageDialog(null, "You entered wrong value. Please re- enter");
                        grades.requestFocusInWindow();
                        grades.setText("");
                        a = Integer.parseInt(t1.getText());
                        }
                        else
                        {
                            name.requestFocusInWindow();
                            name.setText("");
                            System.out.println(names + "   " + results);
                        }
                    }

}
}
}

Answer 1

要将它们存储在一个数组中，您只需将它们放在第一位。

例如，names数组只是创建一个新数组：

  'String[] namelist = new String[numofnames];'

然后搜索它只需使用for循环并检查索引以查找您要查找的字符串名称。检查它是否匹配。

实施例

for(int x = 0; x<numofnames; x++)
{
   name.toLowerCase();
   namelist.toLowerCase();
   if(name.equals(namelist[x])
    return x; //return whatever you need
}

这应该可以解决这个问题。

声明数组并接受来自用户的输入，记录数据

1 个答案: